How to write an expression using exponents?

A pair of dice is rolled. Find the probability for P(not 2 or not 12)

irakobra [83]

Answer:

There’s only one way to get 12 when 2 dice are tossed, both have to equal 6. There are 6 ways tossing a single die can come out (1,2,3,4,5,6), so if you toss dice, the second die could have any one of six values with each of the numbers that could result from the first toss (e.g., 1 from die 1 and 1,2,3,4,5, or 6 from die 2). So, considering there are 6 ways to fill each of two slots, there are 6 x 6 = 36 possible outcomes of tossing two dice. Only one of them equals 12, so p(12 given 2 dice tossed) = 1/36 = 0.02777777777778.

3 0

2 years ago

Alfredo bought a fishing pole for 60% off it’s original price of $97. If the tax was 4% ( of the sale price), how much did Alfre

maxonik [38]

Answer:

40.4

Step-by-step explanation:

Well...you see, 60% of $97 is equal to 58.2. you can get this by multiplying 97 by 0.60.

so subtract 97 by 58.2 and you will get 38.8, now you will add the tax which is and extra add-on to the prices full value

and it's a 4% tax so you will add for percent to 38.8,

basically multiply 38.8 times 0.04 and you will get 1.6 which you will have to add the your amount to get 40.4.

5 0

2 years ago

Eight people enter a tennis tournament which each person must play every other person exactly once Determine the number of games

LiRa [457]

Answer:

The answer is 28. Hope it helps :D

7 0

2 years ago

Which expression is equivalent to the following complex fraction?

vladimir2022 [97]

Answer:

second 1

Step-by-step explanation:

4 0

2 years ago

Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6

Oksi-84 [34.3K]

Answer:

$-1/3$

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

$9x^2-15x$

Ignore the less than sign and replace it with an equal sign and solve the quadratic for its zeros:

$9x^2-15x=6$

Subtract 6 from both sides:

$9x^2-15x-6=0$

Divide everything by 3:

$3x^2-5x-2=0$

Factor. Find two numbers that equal (3)(-2)=-6 that add up to -5.

-6 and 1 works. Thus:

$3x^2-6x+x-2=0\\3x(x-2)+1(x-2)=0\\(3x+1)(x-2)=0$

Find the x using the Zero Product Property:

$3x+1=0 \text{ or }x-2=0\\x=-1/3\text{ or }x=2$

Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

$x=-1/3$

Assume that the correct symbol is >. Thus,

$x>-1/3$

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

$9x^2-15x$