Answer:
A^2 + B^2 = C^2
Step-by-step explanation:
The applies for right triangle where C is the hypotenuse.
Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]
Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
Answer:
m∠1= 79
Step-by-step explanation:
What we have here is two vertical lines and one intersecting point.
The m∠1 and m∠6 are vertical angles, which means that they equal to each other. So, the equation would be: 6x+25= 10x-11.
Step 1- Subtract 6x to both sides.
6x+25= 10x-11
-6x -6x
25= 4x-11
Step 2- Add 11 to both sides.
25= 4x-11
+11 +11
36= 4x
Step 3- Divide both sides by 4.
<u>36</u>= <u>4x</u>
4 4
x= 9
Now that we know the value of the variable x, substitute it into the equation for m∠1.
m∠1= 10(9)-11
m∠1= 90-11
m∠= 79
<u>Check </u>
m∠6= 6(9)+25
m∠6= 54+25
m∠6= 79
Since m∠1 and m∠6 are vertical angles, they should equal each other.
Answer:
see below
Step-by-step explanation:
On the real number line you can't
to graph them you have to make a Cartesian plane
with x= the real numbers
and y= the imaginary numbers
