Utilizing Lorentz factor;
Lorentz factor = Sqrt (1-u^2/c^2), where u = initial velocity, c = speed of light
But, u/c = 0.960
Therefore,
Lorentz factor = Sqrt (1-0.960^2) = 0.28
For an observer,
t = (Distance to the star*Lorentz factor)/ (u/c) = (14.4*0.28)/0.96 = 4.2 years
Answer:
As block 1 moves from point A to point B, the work done by gravity on block 2 is equal to the change in the kinetic energy of the two-block system.
Explanation:
As block 2 goes down , work is done by gravity on block 2 . This is converted
into kinetic energy of block 1 and block 2 . Work done by gravity is mgh which can be measured easily . kinetic energy of both the blocks can also be measured.
The force exerted(applied) onto a surface by the weight of air
Answer:
The sun rays will be focused at the same distance from the mirror.
Explanation:
Laws of reflection do not depend on the refractive index n any form. Hence, the sun’s rays will be focused the same distance from the mirror.
Answer
given,
mass of the package = 12 kg
slides down distance = 2 m
angle of inclination = 53.0°
coefficient of kinetic friction = 0.4
a) work done on the package by friction is
W_f = -μk R d
= -μk (mg cos 53°)(2.0)
=-(0.4)(8.0 )(9.8)(cos 53°)(2.0)
= -37.75 J
b)
work done on the package by gravity is
W_g = m (g sin 53°) d
= (8.0 )(9.8 )(sin 53°)(2.0 )
=125.23 J
c)
the work done on the package by the normal force is
W_n = 0
d)
the net work done on the package is
W = -37.75 + 125.23 + 0
W = 87.84 J
