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Radda [10]
1 year ago
11

The student measured the extension for five different forces rather than just measuring the extension for one force. Suggest why

.​
Physics
1 answer:
Oksanka [162]1 year ago
4 0

The student measured the extension for five different forces rather than just measuring the extension for one force to identify anomalies. This is further explained below.

<h3>What is measurement?</h3>

Generally, measurement is simply defined as the process of determining the size of something.

In conclusion, The student took five separate measurements of extension for various forces in order to better detect any discrepancies.

Read more about measurement

brainly.com/question/3780384

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Explain ways that weak and strong nuclear forces are alike.
larisa [96]
They both use messenger particles to carry the force. Gluons for the strong force and W and Z for the weak. And both sets of particles solely with the sub atomic particles of the nuclei: quarks and neutrinos. That is, their range is limited to the nuclei of the atoms and the ions.
8 0
3 years ago
It has been suggested that rotating cylinders about 9 mi long and 5.9 mi in diameter be placed in space and used as colonies. Wh
mezya [45]

Answer:

\omega = 4.5\times 10^{-2} rad/s

Explanation:

Given data:

Rotating cylinder length = 9 mi

diameter of cylinder is 5.9 mi

we know that linear acceleration is given as

a =  r ω^2

where ω is angular velocity

so\omega = \sqrt{\frac{a}{r}}

r = \frac{5.9}[2} \frac{1609 m}{1 mi} = 4.746\times 10^{3} m

\omega = \sqrt{\frac{9.80}{4.746\times 10^{3}}}

\omega = 4.5\times 10^{-2} rad/s

7 0
3 years ago
The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object
VashaNatasha [74]

Answer:

m_B > m_A

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

        F = m a

        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

         \frac{F}{m_A} > \frac{F}{m_B}

         m_B > m_A

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

6 0
3 years ago
A cannon of mass 6.43 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7
Nata [24]

Answer:

The velocity of the shell when the cannon is unbolted is 500.14 m/s

Explanation:

Given;

mass of cannon, m₁ = 6430 kg

mass of shell, m₂ = 73.8-kg

initial velocity of the shell, u₂ = 503 m/s

Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.

K.E = ¹/₂mv²

K.E = ¹/₂ (73.8)(503)²

K.E = 9336032.1 J

When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy

change in initial momentum = change in momentum after

0 = m₁u₁ - m₂u₂

m₁v₁ = m₂v₂

where;

v₁ is the final velocity of cannon

v₂ is the final velocity of shell

v_1 = \frac{m_2v_2}{m_1}

Apply the principle of conservation kinetic energy

K = \frac{1}{2}m_1v_1^2 +  \frac{1}{2}m_2v_2^2\\\\K = \frac{1}{2}m_1(\frac{m_2v_2}{m_1})^2 + \frac{1}{2}m_2v_2^2\\\\K = \frac{1}{2}m_2v_2^2(\frac{m_2}{m_1}) + \frac{1}{2}m_2v_2^2 \\\\K = \frac{1}{2}m_2v_2^2 (\frac{m_2}{m_1} + 1)\\\\2K = m_2v_2^2 (\frac{m_2}{m_1} + 1)\\\\v_2^2 = \frac{2K}{M_2(\frac{m_2}{m_1} + 1)} \\\\v_2^2 = \frac{2*9336032.1}{73.8(\frac{73.8}{6430} + 1)}\\\\

v_2^2 = 250138.173\\\\v_2 = \sqrt{250138.173} \\\\v_2 = 500.14  \ m/s

Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s

3 0
3 years ago
Identify the smallest unit of an element
marysya [2.9K]

atom ................................................... sorry for the periods

3 0
3 years ago
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