The student measured the extension for five different forces rather than just measuring the extension for one force. Suggest why
1 answer:
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Answer:
The same as the escape velocity of asteorid A (50m/s)
Explanation:
The escape velocity is described as follows:
where is the universal gravitational constant,
is the mass of the asteroid and
is the radius
and since the scape velocity is 50m/s:
Now, if the astroid B has twice mass and twice the radius, we have that tha mass is:
and the radius is:
inserting these values into the formula for escape velocity:
and we have found that , so the two asteroids have the same escape velocity.
We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.
The answer is
Asteroid B would have an escape velocity the same as the escape velocity of asteroid A
by cosine law we know that
now using above equation
by solving above quadratic equation we have
so it is at distance 124.9 m from deer a