Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
(3) KE = 3 kg m^2/s^2
(4) KE = 4 kg m^2/s^2
Explanation:
(1) Given mass = 0.125 kg
speed = 4 m/s
Since Kinetic energy = (1/2)*m*(v^2)
Plug in the values:
Hence:
KE = (1/2) * 0.125 * (16)
KE = 1 kg m^2/s^2
(2) Given mass = 0.250 kg
speed = 4 m/s
Since Kinetic energy = (1/2)*m*(v^2)
Plug in the values:
Hence:
KE = (1/2) * 0.250 * (16)
KE = 2 kg m^2/s^2
(3) Given mass = 0.375 kg
speed = 4 m/s
Since Kinetic energy = (1/2)*m*(v^2)
Plug in the values:
Hence:
KE = (1/2) * 0.375 * (16)
KE = 3 kg m^2/s^2
(4) Given mass = 0.500 kg
speed = 4 m/s
Since Kinetic energy = (1/2)*m*(v^2)
Plug in the values:
Hence:
KE = (1/2) * 0.5 * (16)
KE = 4 kg m^2/s^2
Answer:
Explanation:
Momentum conservation

Kinetic energy conservation

Solve the system
Answer:
A.
Explanation:
We are given that

Density,
Tension,T=38 N
We have to find the density of liquid.


Volume,V=




Option A is true.
Answer:
The amount of force and the angle between them.
Explanation:
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:
the general equation of acceleration is:
vf = vi + at
assuming the initial velocity (vi) is zero, the equation becomes:
vf = at
v = at