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Solnce55 [7]
3 years ago
8

Evaluate the expression. 32 ÷ 8 · 4 A. 1 B. 8 C. 16 D. 64

Mathematics
1 answer:
Komok [63]3 years ago
5 0
The answer is 16 I meant srry couldn't read it
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Box and tail set up for:
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Assuming that all of the 255 sold seats were filled, then

[tex]\frac{sold}{total} *100\\[percent filled]

(225/260)*100=86.53%

100%-86.53%=13.4%

13.4% of seats are empty!

3 0
3 years ago
Jim runs 12 miles in 4 hours how many feet does he run per minute
hjlf

h= number of hours

m= number of miles

Formula: 4h=12m

(4 hours equals 12 miles)

Divide 4 on each side.

h= 3m

3 miles per hour.

Then, convert miles to feet. And hours to minute.

To do this simultaneously,

Convert miles to feet and hours to minutes.

There should be 3 "fractions" to multiply.

The first should be the original problem:

3miles/1 hour. (3 miles per hour).

The second should be 1 hour/60min. (1 hour per 60 min).

The third should be 5280 ft/1 mile. (5280 feet per mile).

The second and the third fractions are to convert miles to feet and the hours to minutes.

8 0
3 years ago
How do you find the exact cosine or sine value for each given measure of an angle?
Helen [10]

Answer:

REMEMBER:

to find the sine, cosine on the unit circle:

cos a = coordinate value x

sin a = coordinate value of y

Step-by-step explanation:

I'm not sure y'all but i hopes this helps just a remember.

5 0
3 years ago
What does this equal? 2(x-5)-3(4x-2)=6
joja [24]
2x - 10 -12x + 6 = 6 

-10x -4 = 6

-10x = 10

-x = 1

x = -1
3 0
2 years ago
Read 2 more answers
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
3 years ago
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