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Sindrei [870]
3 years ago
5

A microscope has an objective lens with a focal length of 14.0mm . A small object is placed 0.80mm beyond the focal point of the

objective lens.Part A: At what distance from the objective lens does a real image of the object form? Express your answer to two significant figures and include the appropriate units.Part B: What is the magnification of the real image? Express your answer using two significant figures.Part C: If an eyepiece with a focal length of 2.5 cm is used, with a final image at infinity, what will be the overall angular magnification of the object? Express your answer using two significant figures.

Physics
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

A. 260 mm

B. - 18

C. 175

Explanation:

A

The expression for the lens equation is

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{14.0mm} = \frac{1}{14.80 mm} + \frac{1}{v}

\frac{1}{v} = \frac{1}{14.0} - \frac{1}{14.80}

v = 259 mm

   = 260 mm or 26 cm (to 2 s.f)

check the attached files for additional solution

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A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
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Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

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b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

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c)

We now need the time at which y(t') = -64 ft

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