Answer: The molar mass of the unknown compound is 200 g/mol
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for molecular compound)
= freezing point constant = 
m= molality
Weight of solvent (benzene)= 0.250 kg
Molar mass of solute = M g/mol
Mass of solute = 26.7 g
Thus the molar mass of the unknown compound is 200 g/mol
Answer:
3.16×10⁹ pL
Explanation:
Given data:
Volume in mL = 3.16
Volume in picoliters = ?
Solution:
Picoliter and milliliters are units of volume. Milliliter is greater unit than picoliter.
1 mL = 10⁹ pL
Now we will convert the 3.16 mL into pL.
3.16 mL × 10⁹ pL/ 1 mL
3.16×10⁹ pL
For a second order reaction, if (A)^-1 is plotted vs. time is straight line with k= slope of the line,Plot the inverse of concentration of a reactnt verus time.
Second order reaction defined as chemical reactions which is the sum of the exponents in the rate of law of the chemical reaction is equal to two.The such reaction is written as the - r=k(A)2 or r= k(A)(B).
Second order reaction is a type of reaction which is depend on the concentrations of one second order or two first order reactants.Reaction proceeds at rate proportional to the square of the product of the concentration of one reactant, or the product of the concentrations of two reactant.
To learn more about second order reaction here
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