Question

Dry ice is carbon dioxide in the solid state. 1.28 grams of dry ice is placed in a 5.00 L chamber that is maintained at 35.1°C. What is the pressure in the chamber after all of the dry ice has sublimed? Assume ideal gas behavior.

Answer 1

Answer:

0.15atm

Explanation:

Given parameters:

Mass of dry ice = 1.28g

Volume of chamber  = 5L

Temperature  = 35.1°C = 35.1 + 273  = 308.1K

Unknown:

Pressure in the chamber  = ?

Solution:

As we assume ideality for the gases in the cylinder, we use the equation below to solve the problem;

             PV  = nRT

P is the pressure

V  is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹k⁻¹

T is the temperature

 

 Let us find the number of moles;

       Molar mass of CO₂  = 12 + 2(16) = 44g/mol

  Number of moles of  CO₂ = $\frac{mass}{molar mass}$

  Number of moles of CO₂  = $\frac{1.28}{44}$   = 0.03moles

 So;

Input the parameters and solve;

        P x 5  = 0.03 x 0.082 x 308.1

         5P  = 0.73

           P = $\frac{0.73}{5}$   = 0.15atm