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Stells [14]
3 years ago
6

In the periodic table, the elements are organized into groups based on

Chemistry
1 answer:
Pani-rosa [81]3 years ago
8 0
<span>In the periodic table, the elements are organized into groups based on putting together elements with similar properties. For instance, elements in each group have the same number of valence electrons, which makes them form similar bonds. Additionally, elements in the same similar characteristics, such as malleability and magnetism.</span>
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Which statements about exothermic and endothermic reactions are correct? (its a multiple choice question)
geniusboy [140]

Answer:

C)1 and 3 only☺️

Explanation:

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What is the function of tendons?
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Answer:

A tendon is a fibrous connective tissue that attaches muscle to bone. Tendons may also attach muscles to structures such as the eyeball. A tendon serves to move the bone or structure.

Explanation:

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2 years ago
The equation most often associated with Newton's Second Law of Motion is
nignag [31]

Answer:

F = ma or Force = mass x acceleration.

Explanation:

Newtons second law is about the force put onto an object. To find this you would use the formula:

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A 10.5 mL sample of vinegar, containing acetic acid, was titrated using 0.460 M NaOH solution. The titration required 19.13 mL o
laila [671]

Explanation:

Step 1:

A good first step for a problem like this is to write down the chemical formula and balance it.

It appears here that we have 10.5 mL of vinegar, which IS acetic acid, and 19.13 mL of 0.460 M NaOH. That will give us the following balanced chemical equation:

CH3COOH + NaOH ------> NaCH3COO + H2O

All of the constituents come out to a value of 1, conveniently.

Step 2:

Since all of our stoichiometric coefficients are one, we can use a shortcut to answer this equation. I don't know if it has a name, but I just call it the titration formula. It goes something like this:

M1 * V1 = M2 * V2

M stands for Molarity and V stands for volume. 1 and 2 being the before the reaction and after the reaction.

So, our M1 for this is going to be what the question says was used for this titration. That's 0.460M NaOH.

Our V1 is going to be the initial volume of the sample, which was 10.5 mL

Our V2 is going to be 19.13, which is the volume when we're finished.

It's clear that we don't know M2, so let's find it.

Keep in mind that it's easier to convert to liters pretty much always, so I've done that by dividing the mL values each by 1000.

Using some algebra, we can see that we now have:

0.460 M * 0.0105 L = x M * 0.01913 L

Which goes to:

\frac{0.00483mol}{0.01913L} = 0.252 M

<h3>So our M2, the molar concentration of acetic acid in this vinegar, is equal to 0.252 M. </h3>
3 0
3 years ago
The elemental analysis of an organic solid extracted from gum arabic (a gummy substance used in adhesives, inks, and pharmaceuti
Evgesh-ka [11]

Answer:

The molar mass of the organic solid is 120.16 g/mol.

The molecular formula of an organic solid is C_4H_8O_4

Explanation:

Let the molecular mass of an organic solid be C_xH_yO_z

\Delta T_b=K_b\times m

Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl  in Kg}}

where,

\Delta T_f =Elevation in boiling point = =1.5^oC

Mass of organic solid= 0.561 g

Mass of diphenyl = 24.9 g = 0.0249 kg (1 kg = 1000 g)

K_b = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}

{\text{Molar mass of solid}}=120.16 g/mol

\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100

Percentage of carbon in an organic solid = 40.0%

40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

x = 4.0

Percentage of hydrogen in an organic solid = 6.7%

6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100

y = 8.0  

Percentage of hydrogen in an organic solid = 6.7%

53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

y = 4.0

The molecular formula of an organic solid is C_4H_8O_4

8 0
3 years ago
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