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Debora [2.8K]
3 years ago
15

If a club charges an initial fee of $99 to join, and a monthly fee of $45. Write an equation that represents the cost of being a

member of the club. How much will you pay after 5 months?
Mathematics
1 answer:
ANEK [815]3 years ago
8 0
Equation: 99 + 45x, with x as how many ever months.

After five months:
99 + 45(5) = 99 + 225 = $324.
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Thirty-five percent of what number is 10.5?
erastovalidia [21]

30% of 35 = 10.5

35 would be your answer. 

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STALIN [3.7K]

Answer:

<u>395.64 m³</u>

Step-by-step explanation:

<u>Volume (figure)</u>

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12/19*.............................= -12/19
melamori03 [73]

Answer:

\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}

Step-by-step explanation:

\frac{12}{19} \times ..... = -\frac{12}{19}

= \frac{\frac{12}{19}}{-\frac{12}{19}}

= \frac{12}{19} \times -\frac{19}{12}

= -\frac{228}{228}

= \bold{-1}

So, the appropriate value to complete it is -1

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3 years ago
Geometry need to find the lengths of DE , EF AND DF , respectively? ASAP
fredd [130]

Answer:

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Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

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