Let , a, b and c be the length of three sides of triangle, represented in terms of vectors as .
Now, vector of same Magnitude acts as normal vector to each side.
So, equation of any vector p having normal q is given by
Now sum of three vector and it's normal is given as
Cross product of two identical vectors is Zero.
A). They are not similar, because 6/13 is not equal to 8/20
For triangles to be similar, the ratios of sides need to be the same (shortest to shortest, middle to middle, longest to longest). The shortest sides are 6 and 13, respectively, the middle ones are 8 and 20. Because 6/13 is not equal to 8/20, the triangles are not similar.
Answer:
C'(4,4)
Step-by-step explanation:
The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule
(x,y)→(2x,2y)
So,
- A(-3,-1)→A'(-6,-2)
- B(-1,1)→B'(-2,2)
- C(2,2)→C'(4,4)
- D(3,-2)→D'(6,-4)
Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)