Answer:
Step-by-step explanation:do you have the answers to choose from?
Answer:

Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Answer:
EF =
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
=
≈ 5.83 ( to 2 dec. places )
It is not true because if you add in 0 the equation would be 8-4(0)=4(0)
4x0 = 0
so it would be 8-0=0 which doesn't add up.