29/7 how u make mixes

Out of 3000 students in a School of Public Health, 1500 students defined themselves regular dietary supplement users. If you tak

attashe74 [19]

Answer:

The standard error of the proportion is 0.112.

Step-by-step explanation:

The standard error of a proportion is given by the following formula:

$S = \sqrt{\frac{p(1-p)}{n}}$

In which p is the probability of a success and n is the length of the sample.

In this problem

A success is a student defining themselves regular dietary supplement users. Our of 3000 students, 1500 do. So $p = \frac{1500}{3000} = 0.5$ .

We take a sample of 20 of them, so $n = 20$ .

So

$S = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5*0.5}{20}} = 0.112$

8 0

3 years ago

The measure of XYZ is 45. The length of radius YZ is 6 inches. What is the area of sector XYZ?

balandron [24]

Answer:

area of a sector = 14.13 yards²

Step-by-step explanation:

XYZ is a sector of a circle. The radius YZ is 6 inches .The angle of the sector is given as 45°. The area of the sector can be solved as follows.

area of a sector = ∅/360 × πr²

where

r = radius

∅ = center angle

r = 6 inches

∅ = 45°

area of a sector = 45/360 × 3.14 × 6²

area of a sector = 45/360 × 3.14 × 36

area of a sector = 45/360 × 113.04

area of sector = 1/8 × 113.04

area of a sector = 14.13 yards²

6 0

3 years ago

Read 2 more answers

1. The length of a rectangle is 5 mm longer than its width. Its perimeter is more than 30 mm. Let w equal the width of the recta

VLD [36.1K]

The of the rectangle is w > 5mm

4 0

3 years ago

If x2 = 30, what is the value of x?

nataly862011 [7]

Subtract 30, then factor the equation.

... x² = 30

... x² - 30 = 0

... (x -√30)(x +√30) = 0

By the zero product rule, the solutions are values of x that make a factor be zero.

... x - √30 = 0 . . . . the first factor is zero

... x = √30

... x + √30 = 0 . . . . the second factor is zero

... x = -√30

The solutions are . . .

... x = ±√30 . . . . . matches your 3rd choice

6 0

3 years ago

Read 2 more answers

The average life of individual is 70 years. With a standard deviation of 5.5 years. Assume that the lives of these individuals i

Harlamova29_29 [7]

Answer:

The answer is below

Step-by-step explanation:

Given that:

mean (μ) = 70 years, standard deviation (σ)= 5.5 years.

a) The z score measures how many standard deviation a raw score is above or below the mean. It is given as:

$z=\frac{x-\mu}{\sigma}$ , for a sample size of n, the z score is: $z=\frac{x-\mu}{\sigma/\sqrt{n} }$

Given a sample of 5 turtles, we have to calculate the z score for x = 60 and x = 80.

For x = 60:

$z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{60-70}{5.5/\sqrt{5} } =-4.07$

For x = 80:

$z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{80-70}{5.5/\sqrt{5} } =4.07$

The probability that a mean life of a random sample of 5 such turtles falls between 60 and 80 years = P(60 < x < 80) = P(-4.07 < z < 4.07) = P(z < 4.07) - P(z < -4.07) = 1 - 0 = 1 = 100%

b) The z score that corresponds to top 10% is -1.28.

$z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\-1.28=\frac{x-70}{5.5/\sqrt{5} }\\ x-70=-3\\x=70-3\\x=67\ years$

3 0

3 years ago