A 29.00 mL sample of an unknown H3PO4 solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 2

Question

Ira Lisetskai [31]

3 years ago

6

A 29.00 mL sample of an unknown H3PO4 solution is titrated with a 0.130 M NaOH solution. The equivalence point is reached when 2

7.73 mL of NaOH solution is added.

Chemistry

1 answer:

beks73 [17] · Answer 1 · 2022-08-12T09:05:36+03:00

beks73 [17]3 years ago

6 0

I am first assuming that you want the molarity of the acid. Use the formula $M_{a} V_{a} = M_{b}V_{b}$ which is the titration formula. M is molarity (a is of acid and b is of base) and V is volume in mL (a is of acid and b is of base). Plugging in gives us $(29 mL)(M_{a}) = (0.130 M)(27.73 mL)$ . Solving gives us $M_{a} = 0.124 M$