Th actual yield of the reaction is 24.86 g
We'll begin by calculating the theoretical yield of the reaction.
2Na + Cl₂ → 2NaCl
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced = 2 × 58.5 = 117 g
From the balanced equation above,
46 g of Na reacted to produce 117 g of NaCl.
Therefore,
11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.
Thus, the theoretical yield of NaCl is 29.25 g.
Finally, we shall determine the actual yield of NaCl.
- Theoretical yield = 29.25 g
Actual yield = Percent yield × Theoretical yield
Actual yield = 85% × 29.25
Actual yield = 0.85 × 29.25 g
Actual yield = 24.86 g
Learn more about stoichiometry: brainly.com/question/25899385
Answer:
huhuhuhuhuhuhuhhihihihuhuhuhjgjfngnvnffv 42.6j
Explanation:
Answer:
Explanation:
The SI unit for mass is the KG
Answer:
The products formed are
2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol
The products should be in equal ratio since an equipmolar amount of acetone and 2,4-dimethylpentan-3-one was initially present as reactants
Explanation:
Ketones reacts with gridnard reagents to form tertiary alcohol, and since acetone and 2,4-dimethylpentan-3-one are both ketones, gridnard reagent reduced both to tertiary alcohols:2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol
