3 years ago

Solve A and B a.g/-4≥17 b.8x+63>127 plz help me quickly!!

2 answers:

6 0

A. $\frac{g}{-4}$ ≥ 17
Multiply by -4 on either sides to cancel out
g ≥ 17

B. 8x + 63 > 127
Take 63 to the other side
8x > 64
Divide by 8 on either sides to isolate x
$\frac{8x}{8}$ > $\frac{64}{8}$
8 and 8 cancels out
x > 8

Travka [436]3 years ago

4 0

G(-1/4)>=17/(-1/4) g>=-68 8x=64 8x/8=64/8 x=8

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$in \: firt \: quadrant \\ sin \frac{\pi}{4} = \frac{ \sqrt{2} }{2} \\ in \: second \: quadrant \\ sin \frac{3\pi}{4} = \frac{ \sqrt{2} }{2} \\ in \: third \: quadrant \: \\ sin \frac{5\pi}{4} = \frac{ - \sqrt{2} }{2} \\ in \: forth \: quadrant \\ sin \frac{7\pi}{4} = - \frac { \sqrt{ 2} }{2} \\ in \: this \: way \: it \: has \: multiple \: soution$