Solve A and B a.g/-4≥17 b.8x+63>127 plz help me quickly!!

2 answers:

6 0

A. $\frac{g}{-4}$ ≥ 17
Multiply by -4 on either sides to cancel out
g ≥ 17

B. 8x + 63 > 127
Take 63 to the other side
8x > 64
Divide by 8 on either sides to isolate x
$\frac{8x}{8}$ > $\frac{64}{8}$
8 and 8 cancels out
x > 8

Travka [436]3 years ago

4 0

G(-1/4)>=17/(-1/4) g>=-68 8x=64 8x/8=64/8 x=8

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Is the relationship shown by the data linear? If so, model the data with an equation.

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Answer:

Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is

Linear Relationship i.e $y-5=2(x+7)$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -7, 5 )

point B( x₂ , y₂) ≡ (-5, 9)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(5))=(\frac{9-(5)}{-5--7})\times (x--7)\\ \\(y-5)=\frac{4}{2}(x+7)\\\\y-5=2(x+7)...............\textrm{which is the required equation of the line AB}$