![\bold{[ \ Answer \ ]}](https://tex.z-dn.net/?f=%5Cbold%7B%5B%20%5C%20Answer%20%5C%20%5D%7D)
![\bold{[ \ Explanation \ ]}](https://tex.z-dn.net/?f=%5Cbold%7B%5B%20%5C%20Explanation%20%5C%20%5D%7D)
-----------------------------------
![\boxed{\bold{[] \ Eclipsed \ []}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbold%7B%5B%5D%20%5C%20Eclipsed%20%5C%20%5B%5D%7D%7D)
The answer to your problem that you are stuck on is 4 which is the third option
Answer:
(m) increased, (b) unchanged. g(x)
(m) decreased, (b) unchanged. m(x)
(m) unchanged, (b) increased. h(x)
(m) unchanged, (b) decreased. n(x)
f(x): m = -1/2 b = 2
g(x): m = 1/3 b = -3
h(x): m = 2 b = 0
probability that the persons IQ falls between 110 and 130 is 0.2286 .
<u>Step-by-step explanation:</u>
Step 1: Sketch the curve.
The probability that 110<X<130 is equal to the blue area under the curve.
Step 2:
Since μ=100 and σ=15 we have:
P ( 110 < X < 130 )=P ( 110−100 < X−μ < 130−100 )
⇒ P ( (110−100)/15< (X−μ)/σ<(130−100)/15)
Since Z = (x−μ)/σ , (110−100)/15 = 0.67 and (130−100)/15 = 2 we have:
P ( 110<X<130 ) = P ( 0.67<Z<2 )
Step 3: Use the standard normal table to conclude that:
P ( 0.67<Z<2 )=0.2286
Therefore, probability that the persons IQ falls between 110 and 130 is 0.2286 .
