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2 years ago

Solve A and B a.g/-4≥17 b.8x+63>127 plz help me quickly!!

2 answers:

6 0

A. $\frac{g}{-4}$ ≥ 17
Multiply by -4 on either sides to cancel out
g ≥ 17

B. 8x + 63 > 127
Take 63 to the other side
8x > 64
Divide by 8 on either sides to isolate x
$\frac{8x}{8}$ > $\frac{64}{8}$
8 and 8 cancels out
x > 8

Travka [436]2 years ago

4 0

G(-1/4)>=17/(-1/4) g>=-68 8x=64 8x/8=64/8 x=8

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2 years ago

Can someone please help me factor this

Dmitry_Shevchenko [17]

Answer:

$\huge\boxed{\bf\:1}$

Step-by-step explanation:

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$

Take $\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 }$ & factorise it at first.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \\= \frac{\left(x-3\right)\left(x-1\right)}{\left(x-4\right)\left(x-3\right)}\\= \frac{x-1}{x-4}$

Now factorise the next set : $\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }$ .

$\frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{\left(x-4\right)\left(x+6\right)}{\left(x-1\right)\left(x+6\right)}\\= \frac{x-4}{x-1}$

Now, multiply the two simplified results.

$\frac{ x ^ { 2 } -4x+3 }{ x ^ { 2 } -7x+12 } \times \frac{ x ^ { 2 } +2x-24 }{ x ^ { 2 } +5x-6 } ^ { }\\= \frac{x-1}{x-4}\times \frac{x-4}{x-1} \\= \frac{\left(x-1\right)\left(x-4\right)}{\left(x-4\right)\left(x-1\right)} \\= \boxed{\bf\: 1}$

$\rule{150pt}{2pt}$

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1 year ago

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DerKrebs [107]

Answer:

I got 0 or 18/5

Step-by-step explanation:

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