Question

Solve A and B a.g/-4≥17 b.8x+63>127 plz help me quickly!!

Answer 1

A. $\frac{g}{-4}$ ≥ 17
Multiply by -4 on either sides to cancel out
g ≥ 17

B. 8x + 63 > 127
Take 63 to the other side
    8x > 64
Divide by 8 on either sides to isolate x
    $\frac{8x}{8}$ > $\frac{64}{8}$
    8 and 8 cancels out
    x > 8

Answer 2

G(-1/4)>=17/(-1/4) g>=-68 8x=64 8x/8=64/8 x=8