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KIM [24]
3 years ago
12

Ƒ(x) = x2 + 2x − 15 to find the solution when ƒ(x) = 0.

Mathematics
2 answers:
NARA [144]3 years ago
8 0

Answer:

x = 3, -5

Step-by-step explanation:

<u>Step 1:  Set the equation to 0</u>

<u />x^2+2x-15=0

<u>Step 2:  Factor</u>

<u />x^2+2x-15=0

x^2-5x+3x-15=0

(x-3)(x+5)=0

<u>Step 3:  Solve for x</u>

<u />x - 3 +3=0 +3

x = 3

x+5-5=0-5

x = -5

Answer:  x = 3, -5

lozanna [386]3 years ago
3 0

Answer:

f = 2 + -15x-1 + x

Step-by-step explanation:

Simplifying

f(x) = x2 + 2x + -15

Multiply f (x)

fx = x2 + 2x + -15

Reorder the terms:

fx = -15 + 2x + x2

Solving

fx = -15 + 2x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.

f = -15x-1 + 2 + x

Simplifying

f = -15x-1 + 2 + x

Reorder the terms:

f = 2 + -15x-1 + x

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Answer:

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