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3 years ago

Simplify the following expression (x-8y)-(2x-4y)

Mathematics

2 answers:

Kipish [7]3 years ago

5 0

Answer:

-x - 12y

Step-by-step explanation:

(x-8y)-(2x-4y)=

x-8y-2x-4y=

x-2x-8y-4y=

-x - 12y

jeka943 years ago

5 0

Answer: -x - 4y

Step-by-step explanation:

(x-8y)-(2x-4y)

x-8y-2x+4y

-x-4y

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How to solve for a, b,

professor190 [17]

It looks like the length of a and b should be the same. You can use the Pythagorean theorem (only works with right triangles):

a² + b² = c² (c is the hypotenuse or the longest side of the triangle, a and b are the other side lengths of the triangle)

a² + (4)² = (5)²

a² + 16 = 25

a² = 9

a = 3

a and b have a length of 3

3 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago

HELP ASAP!!<br> What is the midpoint of the line segment graphed below?

Elis [28]

choice (A) is correct

hope it helps

3 0

1 year ago

Which exponent makes this statement true? 1/5^9= 5^?

Aleks04 [339]

Answer:

The exponent -9 makes the given statement true.

Step-by-step explanation:

We have been given an incomplete mathematical statement and we need to figure out the exponent for 5 on the right hand side to complete the statement.

The given incomplete statement is $\frac{1}{5^{9}}=5^{?}$ .

Let us rewrite the left hand side of the expression by moving the exponential term to the numerator using exponent property. As per this property, if we shift an exponential term from denominator to numerator (or vice versa), the sign of exponent changes.

Therefore, we get:

$5^{-9}=5^{?}$

Now that we have common bases on both the sides, we can equate the exponents. And upon equating the exponents, we can see that the 'question mark' should be replaced by -9 in order for statement to be true.

Therefore, exponent -9 on the right hand side will make the statement true.

5 0

2 years ago

Al said that 3.9 × 6.12 equals 238.68.

horsena [70]

D is your answer. If you multiply the numbers ,you would get 23.868. It is closer to 24.

4 0

3 years ago