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3 years ago

8

4. Which is a chemical property of wood?

1 answer:

scoray [572]3 years ago

4 0

Answer:

burn

Explanation:

when it Burns it turns into ash

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When a baseball is thrown straight upward, what is its acceleration at its greatest height?

Troyanec [42]

I believe the correct answer from the choices listed above is option C. When a baseball is thrown straight upward, <span>its acceleration at its greatest height would be 0 m/s. This is because at max height velocity of the ball is zero which means that acceleration as well is zero. Hope this answers the question. Have a nice day.</span>

5 0

3 years ago

Read 2 more answers

A natural water molecule (H2O) in its vapor state has an electric dipole moment of magnitude, p = 6.2 x 10-30 C.m. (a) Find the

Vika [28.1K]

Answer:

a $D = 3.9 *10^{-12} \ m$

b $\tau_{max} = 1.24 *10^{-25} \ N\cdot m$

c $W = 2.48 *10^{-25} J$

Explanation:

From the question we are told that

The magnitude of electric dipole moment is $\sigma = 6.2 *10^{-30} \ C \cdot m$

The electric field is $E = 2*10^{4} \ N/C$

The distance between the positive and negative charge center is mathematically evaluated as

$D = \frac{\sigma }{10 e}$

Where e is the charge on one electron which has a constant value of $e = 1.60 *10^{-19} \ C$

Substituting values

$D = \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}$

$D = 3.9 *10^{-12} \ m$

The maximum torque is mathematically represented as

$\tau_{max} = \sigma * E * sin (\theta)$

Here $\theta = 90^o$

This because at maximum the molecule is perpendicular to the field

substituting values

$\tau_{max} = 6.2 *10^{-30} * 2*10^{4} sin ( 90)$

$\tau_{max} = 1.24 *10^{-25} \ N\cdot m$

The workdone is mathematically represented as

$W = V_{(180)} - V_{0}$

where $V_{(180)}$ is the potential energy at 180° which is mathematically evaluated as

$V_{(180) } = - \sigma * E cos (180)$

Where the negative signifies that it is acting against the field

substituting values

$V_{(180) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (180)$

$V_{(180) } = 1.24*10^{-25} J$

and

$V_{(0)}$ is the potential energy at 0° which is mathematically evaluated as

$V_{(0) } = - \sigma * E cos (0)$

substituting values

$V_{(0) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (0)$

$V_{(0) } =- 1.24*10^{-25} J$

So $W = 1.24 *10^{-25} - [-1.24 *10^{-25}]$

$W = 2.48 *10^{-25} J$

6 0

4 years ago

a train traveling at 30m/s comes to a complete stop in 20 sec.how far did the train go during the deceleration

elixir [45]

Answer:

600m

Explanation:

v=30m/s

t=20s

s=VT

20×30=600m

3 0

3 years ago

A mass with mass 4 is attached to a spring with spring constant 24 and a dashpot giving a damping 20. The mass is set in motion

aleksandrvk [35]

Answer: $x(t) = 14e^{-2t} - 10e^{-3t}$

Explanation: In a mass-spring-damper system, the differential equation that rules the motion of the mass is: mx" + cx' + kx = 0

Using m = 4, k = 24 and c = 20, we have

4x" + 20x' + 24x = 0

Simplifying, we have

x" + 5x'+ 6x = 0

The characteristic equation of this differential is

$r^{2} + 5r + 6 = 0$

The solutions for the quadratic equation are: $r_{1} = -2$ and $r_{2} = -3$

Hence:

x(t) = $C_{1}e^{-2t} + C_{2}e^{-3t}$

x'(t) = $-2C_{1}E^{-2t} - 3C_{2}e^{-3t}$

To determine the constants, we have the initial conditions x(0) = 4 and

x'(0) = 2, then:

$x(0) = C_{1} + C_{2} = 4\\ C_{1} = 4 - C_{2}$

$x'(0) = -2C_{1} -3C_{2} = 2\\-2(4-C_{2}) -3C_{2} = 2\\C_{2} = -10\\C_{1} = 4 - C_{2}\\C_{1} = 14$

Substituing the constants:

$x(t) = 14e^{-2t} - 10e^{-3t}$

The position function for this system is: $x(t) = 14e^{-2t} - 10e^{-3t}$

7 0

3 years ago

Can someone show me the work of this

Alik [6]

Answer:

use symbollab it will help u

Explanation:

7 0

3 years ago