Answer:
Explanation:
Under the given situation , electron will move in two dimension, one along the plates as well as perpendicular to plates on a curved line. Time required to cover the length of plate with given velocity v and travel half the distance between the plate are equal . Initial velocity in in travelling perpendicular to plated will be zero .
Force on the electron is given by the expression
charge on electron x electric field
F = 1.6 x 10⁻¹⁹ x 9 x 10²
=14.4 X 10 ⁻¹⁷ N
Acceleration = force / mass of electron
=
= 1.58 x 10¹⁴ ms⁻²
If time taken to cover half the distance d = 10 cm be t
d = 1\ 2 a t²
t = √2d / a
t =
= 3.557 x 10⁻⁸ s
If v be the velocity parallel to plate , distance travelled along plate is 50 x 10⁻² m , time taken is 3.557 x 10⁻⁸
= 14.05 x 10⁶ m /s
Here We can use principle of angular momentum conservation
Here as we know boy + projected mass system has no external torque
Since there is no torque so we can say the angular momentum is conserved
now we know that
m = 2 kg
v = 2.5 m/s
L = 0.35 m
I = 4.5 kg-m^2
now plug in all values in above equation
so the final angular speed will be 0.37 rad/s
Answer:
<em>The bullet was 0.52 seconds in the air.</em>
Explanation:
<u>Horizontal Motion </u>
It occurs when an object is thrown horizontally with a speed v from a height h.
The object describes a curved path ruled exclusively by gravity until it hits the ground.
To calculate the time the object takes to hit the ground, we use the following equation:
Note it doesn't depend on the initial velocity but on the height.
The bullet is fired horizontally at h=1.3 m, thus:
t = 0.52 s
The bullet was 0.52 seconds in the air.