Explanation:
Momentum is mass times speed.
p = mv
a) p = (1500 kg) (25.0 m/s) = 37,500 kg m/s
b) p = (40,000 kg) (1.00 m/s) = 40,000 kg m/s
The truck has more linear momentum.
Momentum in the y direction:
pᵧ = (1500 kg) (25.0 m/s) = 37,500 kg m/s
Momentum in the x direction:
pₓ = (1500 kg) (15.0 m/s) = 22,500 kg m/s
Total linear momentum:
p² = pₓ² + pᵧ²
p² = (22,500 kg m/s)² + (37,500 kg m/s)²
p = 43,700 kg m/s
Our sun is a medium mass star, so it wouldn't be too different from the sun's life cycle. It is born, lives for about 10 billion years and then dies. ... As a medium mass star nears the end of its life, it runs out of hydrogen which it has been fusing onto helium in its core for its whole life.
Answers:
a)
b)
Explanation:
a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds are given by:
(1)
Where:
is the angular frequency
is the radius of the orbit of each satellite
is the period of the orbit of each satellite
Isolating :
(2)
Applying this equation to each satellite:
(3)
(4)
(5)
(6)
(7)
(8)
Ordering this periods from largest to smallest:
b) Acceleration is defined as the variation of velocity in time:
(9)
Applying this equation to each satellite:
(10)
(11)
(12)
(13)
(14)
(15)
Ordering this acceerations from largest to smallest:
satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radius 4R.
(i) What does the force exerted on the satellite then become?
eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(ii) What happens to the satellite's speed?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(iii) What happens to its period?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large</span></span>
<span>
</span>