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2 years ago

What is the transfer of energy in the form of rays or waves.?

2 answers:

7 0

Heat energy is transferred through liquids and gases by movement of up-and-down molecules called convection currents. Examples: Hot air balloon, boiling water and weather currents. Heat energy is transferred in the form of invisible waves called INFRARED RADIATION.

asambeis [7]2 years ago

4 0

Ng seismic and translational waves we get the law of michio kaku.

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(a) Calculate the buoyant force on a 2.00-L helium balloon.

iragen [17]

Answer:

0.0239364 N

0.0057879 N

Explanation:

$\rho$ = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

$F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N$

The buoyant force is 0.0239364 N

Net vertical force is given by

$F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N$

The net vertical force is 0.0057879 N

6 0

3 years ago

HELP ASAP PLZ

attashe74 [19]

Answer:

Increases

Explanation:

Because acceleration goes higher

5 0

3 years ago

A time-varying magnetic field is caused by which of the following?

Anit [1.1K]

A time-varying magnetic field can be caused by fluctuating electric fields.

7 0

3 years ago

Read 2 more answers

What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

6 0

3 years ago

Read 2 more answers

Point charges q1= - 4.30 nC and q2=+ 4.30 nC are separated by a distance of 3.00 mm, forming an electric dipole.

sammy [17]

Answer:

a) p = 25.8 10⁻¹² C m , b) The direction of the dipole moment is directed from the negative to the positive charge, c) E = 4.65 10² N/C

Explanation:

a) The dipole moment is

p = 2qa

p = 2 4.30 10⁻⁹ 3.00 10⁻³

p = 25.8 10⁻¹² C m

b) The direction of the dipole moment is directed from the negative to the positive charge, that is, in the opposite direction to the electric field.

c) The torque is

τ = p x E

τ = p E sin θ

E = τ / p sin θ

E = 7.20 10⁻⁹ /(25.8 10⁻¹² sin 36.9)

E = 4.65 10² N/C

We calculate

τ = 15.49 10⁻¹² 4.7 10²

τ = 7.28 10⁻⁹ N m

4 0

2 years ago