The third term would be 5h2 because the descending order would be
-2h4 - 8h3 + 5h2 - 2h - 3
Answer:
The correct answer is 3x
Step-by-step explanation:
Add 2x and x
~Hoped this helped~
~Brainiliest, please?~
5 and 3 are two primary numbers for this question
The probability of losing a data packet is 0.010.
Therefore the probability of successfully sending a data packet (not losing a data packet) is
p = 1 - 0.010 = 0.99
In 100 packet transmissions (independent events), the probability of success is
0.99¹⁰⁰ = 0.3660
The probability of losing a data packet is
1 - 0.366 = 0.6340
Answer:
The probability of resending a data packet is 0.6340
Probability that nbr1 is a boy is p1 = 6/10.
Probability that nbr2 is a boy, given 5 boys left is 5/9
Probability that nbr3 is a boy given 4 boys left is 4/8
Probability that nbr 4 is a boy given 3 boys left is 3/7
Approximately 0.071 or 7.1%
