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ruslelena [56]
3 years ago
9

Considerando que você comece a caminhar em velocidade constante, inicialmente a 350 m de um ponto referencial escolhido. Você ca

minha a 1 m/s no sentido de encontro desse referencial. Podemos dizer que a Equação Horária desse MRU e o tipo de movimento são, respecitvamente:
Escolha uma:

a. S(t)=350−1t, movimento retrógrado


b. S(t)=350−1t, movimento progressivo.


c. S(t)=350+1t, movimento progressivo


d. S(t)=−350+t, movimento progressivo.


e. S(t)=350+1t, movimento retrógrado.
Physics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

a. S(t)=350−1t

Explanation:

To determine the equation of motion you take into account the general form of motion with constant velocity:

S(t)=S_o+vt    ( 1 )

So is the initial position from a specific reference frame. In this case is 350 m.

v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.

You replace the values of So and v in the equation ( 1 ) and you obtain:

S(t)=350-(1m/s)t

Hence, the answer is:

a. S(t)=350−1t

- - - - - - - - - - - - - - - - - - - - -

Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:

             (1)

Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.

v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.

Você substitui os valores de So ev na equação (1) e obtém:

Portanto, a resposta é:

uma. S (t) = 350-1t, movimento retrógrado

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