From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.
We make use of the following formula
mv²/2 = F'd................... Equation 1
Where
- m = mass of the arrow
- v = velocity of the arrow
- F' = average stopping force acting on the arrow
- d = distance of penetration
Make F' the subject of the equation
F' = mv²/2d.................. Equation 2
From the question,
Given:
- m = 20 g = 0.02 kg
- v = 60 m/s
- d = 40 cm = 0.4 m
Substitute these values into equation 2
Hence, The average stopping force acting on the arrow is 90 N
Learn more about average stooping force here: brainly.com/question/13370981
The ability of the ground water to pass through the pore spaces in the rock is described as the rock's permeability. Permeable layers of rock that store and transport water are called aquifers.
Answer:
the correct answer is c, they will accelerate away from each other at different speeds. the 80kg will go faster due to less mass
Series Circuit
A series circuit there is only one path for the electrons to flow (see image of series circuit). The main disadvantage of a series circuit is that if there is a break in the circuit the entire circuit is open and no current will flow. An example of a series would the the lights on many inexpensive Christmas trees. If one light goes out all of them will.
Parallel Circuit
In a parallel circuit the different parts of the electric circuit are on several different branches. There are several different paths that electrons can flow. If there is a break in one branch of the circuit electrons can still flow in other branches (see image of parallel circuit). Your home is wired in a parallel circuit so if one light bulb goes out the other will stay on.
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Answer:
c.) 25 N
Explanation:
We find the volume of the brick, knowing that the volume of a cube is given by the formula:
![l=0,1 metros \\V=l^{3}\\V=(0,1\: \: m)^{3}=0,001\: \: m^{3}](https://tex.z-dn.net/?f=l%3D0%2C1%20metros%20%5C%5CV%3Dl%5E%7B3%7D%5C%5CV%3D%280%2C1%5C%3A%20%5C%3A%20m%29%5E%7B3%7D%3D0%2C001%5C%3A%20%5C%3A%20m%5E%7B3%7D)
being l the side of the cube, which in this case is 10 cm or 0,1 m. Now we find the mass of the object, knowing the density and the Volume of the cube:
![m=V*d\\m=(0,001 \:\:m^{3})(2500 \: \: \frac{Kg}{m^{3}})=2,5 \:\: Kg](https://tex.z-dn.net/?f=m%3DV%2Ad%5C%5Cm%3D%280%2C001%20%5C%3A%5C%3Am%5E%7B3%7D%29%282500%20%5C%3A%20%5C%3A%20%5Cfrac%7BKg%7D%7Bm%5E%7B3%7D%7D%29%3D2%2C5%20%5C%3A%5C%3A%20Kg)
We find the weight by multiplying the mass of the object with the gravity constant.
![W=m*g=(2.5 \:Kg)*(9,81 \:m/s^{2} )=24,5 N\approx25\: N](https://tex.z-dn.net/?f=W%3Dm%2Ag%3D%282.5%20%5C%3AKg%29%2A%289%2C81%20%5C%3Am%2Fs%5E%7B2%7D%20%29%3D24%2C5%20N%5Capprox25%5C%3A%20N)