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Lubov Fominskaja [6]

3 years ago

9

1. Which of the following could be an example of a function with a domain (-∞, ∞) and a range (-∞, 2)?

1 answer:

salantis [7]3 years ago

7 0

That would be choice C the limit of f(x) is 2.

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14.371 value of 1 in decimal form

artcher [175]

0.001. hope that helped

7 0

3 years ago

Divide x^3+2 by x+1<br> long division<br> ppleeease! :)

anzhelika [568]

Long division:   (x³ + 2) ÷ (x + 1)

   <u>    </u><u>x² – x + 1   </u>
x³ + 0x² + 0x + 2 | x + 1
<u>– x³ – x²</u> ⋮   ⋮
– x² + 0x   ⋮
<u>+ x² + x</u><span>   ⋮</span>
+ x + 2
<span> </span> <u>– x – 1</u>
+ 1

    Quotient:   Q(x) = x² – x – 1;

Remainder:   R(x) = + 1.

I hope this helps. =)

3 0

3 years ago

Which describes the graph of y=(x+3)^2-4?

worty [1.4K]

The answer to your question is option d as x is positive ( making it open up), and the vertex is (-3,-4)

8 0

3 years ago

Read 2 more answers

PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!

Svetach [21]

$h(x)=20e^{kx}$

a. If $h(1)=20$ , then $20=20e^k\implies e^k=1\implies k=0$ .

b. If $h(1)=40$ , then $40=20e^k\implies e^k=2\implies k=\ln2$ , so that $2k+1=2\ln2+1$ .

c. If $h(1)=10$ , then $10=20e^k\implies e^k=\dfrac12\implies k=-\ln2$ , so that $k-3=-\ln2-3$ .

3 0

3 years ago

PLEASE, I NEED HELP FOR A CLASS. The length of triangle base is 26. A line, which is parallel to the base divides the triangle i

sasho [114]

Answer:

$DE=18.38$

Step-by-step explanation:

It is given that the length of triangle base is 26 that is BC=26.

A line, which is parallel to the base divides the triangle into two equal area parts.

Therefore, from the given information, $\frac{{\triangle}ADE}{ar ABC}=\frac{1}{2}$ .

Now, since it is given that A line, which is parallel to the base divides the triangle into two equal area parts, thus

$\frac{ar ADE}{arABC}=\frac{1}{2}=\frac{(DE)^{2}}{(BC)^{2}}$

⇒ $\frac{(DE)^{2}}{(BC)^{2}}=\frac{1}{2}$

⇒ $\frac{(DE)^{2}}{(26)^{2}}=\frac{1}{2}$

⇒ $(DE)^{2}=13{\times}26=338$

⇒ $DE=18.38$

7 0

3 years ago