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weeeeeb [17]
3 years ago
12

Due at 8:20 am and it’s currently 2:20 am! Please help me. Do NOT send links, it’s irritating and it is a waste of time. Thank y

ou!
Balance the following equation, then solve for the heat of the combustion reaction (ΔH rxn) of glucose:

C6H12 (g) + O2 (g)-> CO2 (g) + H2O (g)

Chemistry
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

1,9,6,6

Explanation:

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A solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12
Colt1911 [192]
POH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

pOH = 12
8 0
3 years ago
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In the process of preparing liquid air for fractional distillation, one fraction will be separated as a solid. What is the chemi
makvit [3.9K]

Answer:

carbon dioxide CO₂

Explanation:

Each gas has a characteristic boiling point. You can separate a random sample of gases by gradually cooling the sample until each component gas liquifies. Some compounds, such as CO₂ never liquify. Instead, they turn directly into solids.

3 0
3 years ago
What is the relationship between atoms and mass?
castortr0y [4]

Answer:

Explanation:

A property closely related to an atom's mass number is its atomic mass. The atomic mass of a single atom is simply its total mass and is typically expressed in atomic mass units or amu.

6 0
3 years ago
A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g
Lynna [10]

Answer:

\%NaHCO_3=61.2\%

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

NaHCO_3+HA\rightarrow NaA+H_2O+CO_2

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%

Best regards.

5 0
3 years ago
When a reaction forms between atoms with ground state electron configuration 1s22s2 and 1s22s22p5 the predominant type of bond f
Arisa [49]
C. Ionic is the answer
6 0
2 years ago
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