Question

A circle is centered at K(0, 0). The point U(6, -4) is on the circle. Where does the point V(square root 2, -7) lie

Answer 1

Answer:

V is inside the circle.

Step-by-step explanation:

We work out the radius of the circle which is the distance between K (0,0) and (6, -4).

Radius = √[(6 - 0)^2 + (-4 - 0)^2]

= √(16 + 36)

= √52.

Now find the distance of point V from K(0,0):

= √((√2-0)^2 + (-7-0)^2]

= √(2 + 49)

= √51.

This is less than the radius of the circle, so V lies inside it.