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3 years ago

A circle is centered at K(0, 0). The point U(6, -4) is on the circle. Where does the point V(square root 2, -7) lie

Mathematics

1 answer:

Dominik [7]3 years ago

5 0

Answer:

V is inside the circle.

Step-by-step explanation:

We work out the radius of the circle which is the distance between K (0,0) and (6, -4).

Radius = √[(6 - 0)^2 + (-4 - 0)^2]

= √(16 + 36)

= √52.

Now find the distance of point V from K(0,0):

= √((√2-0)^2 + (-7-0)^2]

= √(2 + 49)

= √51.

This is less than the radius of the circle, so V lies inside it.

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Graph the system of linear equations. -1/2y=1/2x+5 and y=2x+2

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Given as :

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So, The points are (x , y ) = ( $\dfrac{-2}{3}$ , $\dfrac{2}{3}$ )

Now, plotting the points on x-y coordinate graph

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