<u>Answer:</u>
Force = 20N
acceleration (a) = 1.5 m/s²
Mass of object (m) = ?
<u>From Newtons II law</u>
<em> F = m. a N</em>
m = F/a
m = 20/1.5
<em> m = 13.34 Kg</em>
<em>Mass of an object is 13.34 Kg</em>
1 kg=100000 cg
2 kg=200000 cq
If mass is the quantity then kg is the S.I
2 kg=2kg
Solution:
initial sphere mvr = final sphere mvr + Iω
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m²
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω
where: ω = 2.87 rad/s
So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)²
E = 12.64 J becomes PE = mgh, so
12.64 J = 2.3 kg * 9.8m/s² * h
h = 0.29 m
h = L(1 - cosΘ) → where here L is the distance to the CM
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ
Θ = arccos((1-0.29)/1) = 44.77 º
Answer:
Explanation:
R = Horizontal range of projectile = 75 m
v = Velocity of projectile = 37 m/s
g = Acceleration due to gravity = 
Horizontal range is given by
The angle at which the arrow is to be released is .
Answer:
different value to l if n=5 are 0,1,2,3,4
