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Strike441 [17]
3 years ago
8

Please Help Quick ASAp Hurry

Physics
1 answer:
mamaluj [8]3 years ago
5 0

Answer:

it maybe correct

Explanation:

You can feel an increase of pressure on your eardrums. ... The deeper you go under the sea, the greater the pressure of the water pushing down on you

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The Outlaw Run roller coaster in Branson, Missouri, features a track that is inclined at 84 ∘ below the horizontal and that span
harina [27]

Answer:

Explanation:

a)

Ff = μmgcosθ

Ff = 0.28(1600)(9.8)cos(-84)

Ff = 458.9217...

Ff = 460 N

b)  ignoring the curves required at top and bottom which change the friction force significantly, especially at the bottom where centripetal acceleration will greatly increase normal forces and thus friction force.

W = Ffd

W = 458.9217(-49.4/sin(-84)

W = 22,795.6119...

W = 23 kJ

c) same assumptions as part b

The change in potential energy minus the work of friction will be kinetic energy.

KE = PE - W

½mv² = mgh - (μmgcosθ)d

v² = 2(gh - (μgcosθ)(h/sinθ))

v = √(2gh(1 - μcotθ))

v = √(2(9.8)(49.4)(1 - 0.28cot84))

v = 30.6552...

v = 31 m/s

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2 years ago
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Sergeeva-Olga [200]

Answer:

counter question if you get out the shower clean then how does your towel get dirty?

3 0
3 years ago
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According to Dr. paul Narguizian professor of Biology and Science Education at California State University, ______ are generaliz
Mazyrski [523]

Answer:

I believe the correct answer would be A :)

Explanation:

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2 years ago
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Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
Kay [80]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

3 0
3 years ago
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