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lara31 [8.8K]
3 years ago
7

What is the equivalent resistance of a series circuit with the following resistors: 10 ohms, 35 ohms, and 150 ohms?

Physics
2 answers:
Eva8 [605]3 years ago
3 0

Answer: R=10+35+150

R=195Ω

Explanation:

Sunny_sXe [5.5K]3 years ago
3 0

Answer:195ohms

Explanation:

for series connection we get

Equivalent resistance=10+35+150

Equivalent resistance=195ohms

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Which object is in static equilibrium?
umka21 [38]

There are two types of equilibrium in mechanics.One is called static equilibrium and the other one is called dynamic equilibrium. In both the cases of mechanical equilibrium,the net force acting on the particle is zero.

A body is said to be in dynamic equilibrium if the net force acting on a moving body is zero.There will be no acceleration of the body.The body will continue its uniform motion without change in its direction and speed.

The body is said to be in static equilibrium if the net force acting on a body at rest is zero.As the net force is zero,the body will not undergo motion. It is due to the inertia of the body.

The two equilibrium are the direct consequences of Newton's first law which tells that a body will continue to be at state of rest or uniform motion along a straight line unless and until it is compelled by some external unbalanced force.Hence as long as net force on the body is zero,the body at rest will satisfy static equilibrium.

Out of the four options given in the question only third option is right which tells that a book that has no net force acting on it and sitting on a table is under static equilibrium. If the net force is not zero,the body can not be under static equilibrium.The book resting on a table imparts a force equal to its weight on the table and table in turn gives the normal reaction in vertically upward direction.The gravity pulls the book in vertically downward direction with a force equal to its weigh.Hence the net force is zero.So the table will be at rest.

If the net force is not zero,the body can not be under static equilibrium.

Hence option 3 is right.



4 0
3 years ago
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What is the polarity of each of the earths magnetic poles ? Explain you answer
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Answer:

When you put un-like poles together (South facing North) you can feel magnetic attraction. In the Northern Hemisphere, your compass needle points North, but if you think about it for a moment, you will discover that the magnetic pole in the Earth's Northern Hemisphere has to be a South polarity.

3 0
3 years ago
Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will
denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

                 W_{net} = \Delta K

Also,   \Delta K = K_{initial} - K_{final}

                        = (0 - 4.0 \times 10^{-17}) J

                        = -4.0 \times 10^{-17} J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

                w = -Fd

       -4.0 \times 10^{-17} J = -F \times 0.3 m

                F = 1.33 \times 10^{-16}  

Therefore, relation between electric field and force is as follows.

              E = \frac{F}{q}

                 = \frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}

                 = 0.831 \times 10^{3} C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is 0.831 \times 10^{3} C.

3 0
3 years ago
The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca
Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J

Calculating point A:

when the value is 0.38

\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\

                   =2.632

\to D(a.v) = \frac{1}{0.38} \times 206265\\

               =542,802.6

Calculating point B:

when the value is 0.75

\to D(PC)=\frac{1}{0.75}

                =1.33

\to D(a.v) = \frac{1}{0.75} \times 206265\\

             =275,020

Calculating point C:

when the value is 0.28

\to D(PC)=\frac{1}{0.28}

                =3.571

\to D(a.v) = \frac{1}{0.28} \times 206265\\

               =736660.7

Calculating point D:

when the value is 0.42

\to D(PC)=\frac{1}{0.42}

                =2.38

\to D(a.v) = \frac{1}{0.42} \times 206265\\

               =490910.7

Calculating point E:

when the value is 0.31

\to D(PC)=\frac{1}{0.31}

                =3.226

\to D(a.v) = \frac{1}{0.31} \times 206265\\

               =665370.97

6 0
3 years ago
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