Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
B] Let the mass of plane be m, force on backwheels be Nb and nosewheel be Nn
Torque equation about nose wheel,
mg*(2.58-0.8) - Nb *(3.02-0.8) = 0
Nb = mg*(2.58-0.8)/(3.02-0.8) = 0.8018 mg
Nn = mg - Nb = (1-0.8018) mg = 0.1982mg
Weight percentage supported by front wheel = 19.82% answer
Answer:
The output power the weightlifter is 2916.67 W.
Explanation:
Given;
weight lifted, W = 700 N
height the weight is lifted, h = 2.5 m
time taken to lift the weight, t = 0.60 s
The output power the weightlifter is calculated as;
Power = Energy applied / time taken
Energy applied = weight lifted x height the weight is lifted
Energy applied = 700 x 2.5
Energy applied = 1750 J
Power = 1750 / 0.6
Power = 2916.67 J/s = 2916.67 W.
Therefore, the output power the weightlifter is 2916.67 W.
Answer:
Explanation:
charge, q = 10 C
time, t = 2 micro second
Current, i = q / t
i = 10 / (2 x 10^-6) = 5 x 10^6 A
(a)
distance, d = 1 m
the formula for the magnetic field is given by
B = 1 Tesla
Now the distance is d' = 1 km = 1000 m
B' = 0.001 Tesla
(b) The magnetic field of earth is Bo = 3 x 10^-5 tesla
B / Bo = 3.3 x 10^4
B'/Bo = 33.3