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Molodets [167]
3 years ago
14

Main Idea: To evaluate an exponential growth or decay function, substitute a value for the exponent variable and simplify.

Mathematics
1 answer:
Helen [10]3 years ago
3 0
If there is more to the answer than what I give please ask for more!

With F(x) = 3^{x} we can find F(4) by substituting 4 into the main function.

So it would look like this: F(4) = 3^{4} = 3*3*3*3 = 81

Hope this helps!
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Simplify the radical expression63x^15y^9/7xy^11
Andre45 [30]
Are the 63x and the y being added or multiplied?

3 0
3 years ago
Please helppppppp ❤️
liberstina [14]

Answer:

Inverse of f exists.

Step-by-step explanation:

From the graph attached,

If we do the horizontal line test for the function graphed,

We find the function as one to one function.

In other words for every input value (x-value) there is a different output value.

Since, for one-to-one functions, inverse of the functions exist.

Therefore, the answer will be,

The inverse of 'f' exists.

7 0
3 years ago
How does tan 135 degrees compare to tan -135 degrees
Anna007 [38]
Evaluating the tangent function for the two values we obtain the following:
tan 135=tan(135+180)=tan 315=-1

next:
tan -135=tan(180-135)=tan 45=1
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3 0
3 years ago
Choose the best description for the real number 34 over 3 .
ycow [4]

Answer: the first one is irrational because it is a repeating fraction.

the third is square root of 7 is less than 14/5

the fourth is negative 5 over 6, negative 5, negative 31 over 6, negative square root 26

Step-by-step explanation: Hope this helps !

7 0
2 years ago
Find the distance between A and B.
Papessa [141]

Answer:

The result is d = 2\sqrt{5} units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2} Where the first coordinate is (x_{1},y_{1}) and  the second coordinate is (x_{2}, y_{2}).

-Use the coordinates A and B for the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

-Then, you solve the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

d = \sqrt{(4)^2 + (2)^2}

d = \sqrt{16 + 4}

d = \sqrt{20}

d = 2\sqrt{5}

So, therefore the distance is 2\sqrt{5} units.

7 0
3 years ago
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