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Lelu [443]
3 years ago
5

How many constitutionally isomeric monochlorination products are possible from the following?a. 2-Methylpentane b. 3-Methylpenta

ne c. 2,2-Dimethylbutane d. 2,3-Dimethylbutane
Chemistry
1 answer:
Verdich [7]3 years ago
3 0

Answer:

a. 5

b. 4

c. 3

d. 2

Explanation:

How many constitutionally isomeric monochlorination products are possible from the following?

a. 2-Methylpentane

In 2-methylpentane, there are five possible monochlorinated substitutional products in the reaction of chlorination of 2-methylpentane in the presence of sunlight.

b. In 3-methylpentane there are four possible monochlorinated substitutional products in the reaction of chlorination of 3-methylpentane in the presence of sunlight.

c. In 2,2-Dimethylbutane there are three possible monochlorinated substitutional products in the reaction of chlorination of 2,2-Dimethylbutane in the presence of sunlight.

d. In 2,3-Dimethylbutane there are two possible monochlorinated substitutional products in the reaction of chlorination of 2,3-Dimethylbutane  in the presence of sunlight.

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What happens when the dynamic equilibrium state of a system is disturbed by changing the conditions?
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2 years ago
A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and<br> 32 C.
lisabon 2012 [21]

Answer:

1255.4L

Explanation:

Given parameters:

P₁  = 928kpa

T₁  = 129°C

V₁  = 569L

P₂ = 319kpa

T₂  = 32°C

Unknown:

V₂  = ?

Solution:

The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

P, V and T are pressure, volume and temperature

where 1 and 2 are initial and final states.

Now,

 take the units to the appropriate ones;

             kpa to atm,  °C to K

P₂ = 319kpa in atm gives 3.15atm

P₁  = 928kpa gives 9.16atm

T₂  = 32°C gives 273 + 32  = 305K

T₁  = 129°C gives 129 + 273  = 402K

Input the values in the equation and solve for V₂;

        \frac{9.16  x 569}{402}   = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

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3 years ago
How many moles are in 155 grams of aluminum
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Answer:

wads

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wadsdw

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