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3 years ago

If a 22.4 L volume of a sample of gas has a density of 0.900 grams/L at 1.00 atm and 0.00°C. Given

Chemistry

1 answer:

disa [49]3 years ago

4 0

Answer:

Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)

Explanation:

Use Ideal Gas Law formula to determine formula weight and compare to formula weights of answer choices.

PV = nRT = (mass/fwt)RT => fwt = (mass/Volume)RT = Density x R x T

Density = 0.900 grams/L

R = 0.08206 L·atm/mole·K

T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)

= 20.1 g/mol => Neon (Ne)

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How many atoms of carbon are represented in 3CH3CH20

pishuonlain [190]

6 carbon atoms

          H H
         | |
3 x   H - C - C - O - H
   | |
      H H

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3 years ago

Please help, with step by step work

natali 33 [55]

$\qquad$ ☀️ $\pink{\bf{ {Answer = \: \: 85.57g }}}$

Molar mass of $\bf Cu_2O$

$\qquad$ $\twoheadrightarrow\sf 63.546 \times 2 +16$

$\qquad$ $\pink{\twoheadrightarrow\bf 143.092 g}$

As we know–

1 mol = $\bf 6.02×10^{23}$ formula units

1 mol $\bf Cu_2O$ = 143.092 g = $\bf 6.02×10^{23}$ formula units

Henceforth –

$\bf 3.60×10^{23}$ formula units $\bf Cu_2O$ –

$\qquad$ $\sf :\implies \dfrac{143.092 \times3.60×10^{23 }}{6.02×10^{23}}$

$\qquad$ $\sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23 }}}{6.02×\cancel{10^{23}}}$

$\qquad$ $\pink{:\implies\bf 85.57 g}$

5 0

2 years ago

2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the

solmaris [256]

Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball = 10kg

Height of the rail = 20m

Unknown:

Velocity at the bottom of the rail = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

V² = U² + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

the ball was rolled from rest, U = 0

V² = O² + 2 x 9.8 x 20

V = 19.8m/s

3 0

3 years ago

An organism that contains chloroplasts is able to produce food by the process of

den301095 [7]

An organism that contains chloroplasts is able to produce food by the process of "Photosynthesis"

Hope this helps!

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3 years ago

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the

butalik [34]

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we calculate how many HCl moles reacted, using the given concentration and volume:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We determine how many NaOH moles reacted:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:

5.165 mmol NaOH * $\frac{1mmolH_3PO_4}{3mmolNaOH}$ = 1.722 mmol H₃PO₄

Finally we determine the H₃PO₄ solution concentration:

1.722 mmol / 10.0 mL = 0.172 M

5 0

3 years ago