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AlexFokin [52]
3 years ago
11

False or true: if a substance is reduced, it gains electrons.

Chemistry
1 answer:
kari74 [83]3 years ago
3 0
The Following Statement is True.
You might be interested in
The concentration of the KCN solution given in Part A corresponds to a mass percent of 0.473 %. What mass of a 0.473 % KCN solut
tiny-mole [99]
If the Ka of HCN = 5.0 x 10^-10
Since
(Ka) (Ka) - 1 x 10^ -14
then
the Kb of its conjugate base (CN-) = 2.0 X 10^-5

since
pH + pOH = 14
when the pH = 10.00
then
the pOH = 4.00
& the OH-
would then equal 1.0 X 10^-4

NaCN as a base does a hydrolysis in water:
CN- & water --> HCN & OH-
notice that equal amounts of OH- & HCN are formed

Kb = [HCN] [OH-] / [CN-]

2.0 X 10^-5 = [1.0 X 10^-4] [1.0 X 10^-4] / [CN-]

[CN-] =(1.0 X 10^-8) / (2.0 X 10^-5)

[CN-] = (5.0 X 10^-4)

that's 0.00050 Molar
which is 0.00050 moles in each liter of aqueous KCN solution
which is
0.00025 moles KCN in 500. mL of aqueous KCN solution

use molar mass of KCN, to find grams:
(0.00025 moles KCN) (65.12 grams KCN / mole) = 0.01628 grams of KCn

which is 16.3 mg of KCN
& rounded to the 2 sig figs which are showing in the Ka of HCN , "5.0" X 10^-10
your answer would be
16 mg of KCN

sorry even after making a correction in calcs , I don't get one of your answers.
the only way that I could get one of them is to pretend that yours was a 1 sig fig problem,
in which case your 16 mg would round off to 20 mg.
but you have 3 sig figs in "500. ml", & 2 sig figs in both the "pH of 10.00."
& The Ka of HCN = "5.0 x 10^-10."

it does however take 12 mg of NaCN, to make 500. mL of aqueous solution pH of 10.00. the molar mass of NaCN has the smaller molar mass of 49.00 grams per mole.
maybe they meant NaCN, but wrote KCN instead.

I hope i answered this correctly for you.
8 0
4 years ago
Part A How much time (in minutes) will it take for the water heater to heat the 5.5 L of water from 23 ∘C to 43 ∘C? (Assume that
harina [27]

Answer:

Time = t = 30.01 minutes

Explanation:

The missing part of the question is that "The water heater power rating is 255 Watts, where 1 Watt = 1 J/s.

Firstly, calculating the work done by water heater to heat 5.5 L of water from 23° C to 43°C.

Work Done = Q = m C ΔT

where,

Q = Heat Transfer

m = mass of water

m = Density x Volume = 1 g/mL x 5.5 L = 1000g/L x 5.5L = 5500 g

ΔT = Temperature Difference = 43-23 = 20°C

C = Heat Capacity of Water = 4.186 J/g °C

Therefore,

Q = (5500g)(4.186J/gC) (20C)\\Q = 460460 J

Since, Power can be given as Work done per unit time,

P = \frac{W}{t}

or, in this case,

P = \frac{Q}{t}\\

Here,

P = 255W or P = 255J (Since 1W = 1J)

P=\frac{Q}{t}\\255 = \frac{460460}{t}\\t = \frac{460460}{255}\\t = 1805.72 s\\t = \frac{1805.72}{60}\\t = 30.01 min

3 0
3 years ago
A certain element forms an ion with 36 electrons and a charge of +2. identify the element
Dovator [93]
The answer is Strontium or Sr

Hoep this helps
6 0
4 years ago
Read 2 more answers
Is iced coffee a solution?
kodGreya [7K]
No why are you asking this question?
5 0
3 years ago
What effect did removing prey have on predators
Zielflug [23.3K]

Answer:

The predator population declines

4 0
3 years ago
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