Answer:
Explanation:
distance covered by ice cube = 0.5 m
force acting downwards = mgsin49
force of friction acting along surface upwards
= mgcos49 x .16 ( reaction force of inclined surface R = mgcos49.)
net force acting downwards
mgsin49 - mgcos49 x .16
mg (sin49 - cos49 x .16 )
net acceleration downwards
g (sin49 - cos49 x .16 )
= (.7547 - .105 ) x 9.8
= 6.367 m / s²
s = ut + 1/2 at²
0.5 = 0 + 1/2 x 6.367 x t²
t² = .1570
t = .4 s
b )
Let required inclination be θ
in the second case net acceleration
a = g ( sin θ - .385 cosθ )
s = ut + 1/2 at²
0.5 = 0 + 1/2 x g ( sin θ - .385 cosθ ) x .4 x .4
( sin θ - .385 cosθ ) = .6377
sin θ = .385 cosθ + .6377
θ = 58 degree.
Answer:
0.24T/s
Explanation:
This problem can be solved if use the Lenz's Law, that is
( 1 )
but this emf is for the ring:
and we can replace this value in ( 1 )
where we have taken the area of a circle and a radius of 70cm=0.07m. dB/dt is the ratio of change of the magnetic field. Hence the answer is 0.24T/s
I hope this is useful for you
regards
Answer: Option (B) is the correct answer.
Explanation:
It is advised that while conducting an experiment in a laboratory, always perform it under the supervision of your teacher.
When Hiro accidentally touches the liquid then he should immediately tell his teacher about it so that timely precaution can be taken to avoid any damage or side effect. Also, Hiro should rinse his hand in the sink because it will neutralize or decrease the effect of spilled liquid on his skin.
Thus, we can conclude that he should tell his teacher about the spill and rinse his hand in the sink.
Answer:
a = -1,33 m / s²
Explanation:
This problem is kinematic in one dimension, let's use the equations
v = v₀ + a t
v₀ = v - at
x = v₀ t + ½ a t²
we substitute the first in the second equation
x = (v-at) t + ½ a t²
x -v t = a t² (1 + ½)
a = (x -vt) / t² (1.5)
we calculate
a = (100 - 30 10) / 10² (1.5) =-200 / 150
a = -1,33 m / s²