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Jlenok [28]
3 years ago
5

Accurate _______ is needed in a valid experiment. Hurry, I need help.

Physics
1 answer:
Lorico [155]3 years ago
4 0

Answer: repeatable

Explanation: Accurate repeatable is needed in a valid experiment. I think

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A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak
GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg          

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.  

From the attached figure, the x and y component of forces is given by :

T_{1x} =-T_1 cos (20)

T_{2x} = T_2 cos (40)

mg_x = 0

T_{1y} = T_1 sin (20)

T_{2y} = T_2 sin (40)

mg_y= -mg

Let R_x and R_y is the resultant in x and y direction.

R_x=-T_1 cos (20)+T_2 cos (40)+0

R_y=T_1 sin(20)+T_2 sin(40)-mg

As the system is balanced the net force acting on it is 0. So,

-T_1 cos (20)+T_2 cos (40)+0=0.............(1)

T_1 sin(20)+T_2 sin(40)-100\times 9.8=0..................(2)

On solving equation (1) and (2) we get:  

T_1=866.86\ N (tension on the left rope)

T_2=1063.36\ N (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.                            

7 0
3 years ago
A 5.18x10^4 kg railroad car moves on a frictionless horizontal rails until it hits a horizontal spring stopper with a force cons
nalin [4]

Answer:

The initial velocity of the cart was 0.91m/s.

Explanation:

When the car comes to a stop it has delivered all of its kinetic energy to the spring; therefore,

\dfrac{1}{2}kx^2 = \dfrac{1}{2}  mv^2

solving for v we get:

v = x\sqrt{\dfrac{k}{m} },\\

we put in k = 4.21*10^{5}N/m, m = 5.18*10^{4}kg, and x = 0.32m to get:

v = (0.32m)\sqrt{\dfrac{4.21*10^5}{5.18*10^4} },\\

\boxed{v = 0.91m/s.}

4 0
4 years ago
Imagine that you fill a balloon at sea level (1.0 atm) with 18 L of air. You are taking the balloon to Denver, Colorado, for a b
Salsk061 [2.6K]

Answer:

21.18 L

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 1 atm

Initial volume (V₁) = 18 L

Final pressure (P₂) = 0.85 atm

Final Volume (V₂) =?

With the application of the Boyle's law equation, we can obtain the final volume (i.e the new volume) of the gas as follow:

P₁V₁ = P₂V₂

1 × 18 = 0.85 × V₂

18 = 0.85 × V₂

Divide both side by 0.85

V₂ = 18 / 0.85

V₂ = 21.18 L

Therefore, the new volume of the gas will be 21.18 L

8 0
3 years ago
which surface would have the greatest friction? low carpet a gym floor a brand new sidewalk or gravel​
jasenka [17]
Carpet I’m guessing
7 0
3 years ago
Thermal conductors
ikadub [295]

Answer:

C. are often metals

and

D. have high conductivity

4 0
4 years ago
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