1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maria [59]
3 years ago
14

A child pulls a 3.00-kg sled across level ground at constant velocity with a light rope that makes an angle 30.0° above horizont

al. The tension in the rope is 5.00 N. Assuming the acceleration of gravity is 9.81 m/s2, what is the coefficient of friction between the sled and the ground?
Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

μ = 0.161

Explanation:

Since the tension on the rope (F) is being applied at an angle (θ), it should be decomposed into a vertical and a horizontal component.

The vertical component of the tension on the rope (F*sin(θ)) is pulling the sled upwards, decreasing the normal force.

Therefore, the normal force can be calculated as:

N = m*g - F*sin(\theta)\\N= 3*9.8 - 5*sin(30)\\N= 26.9 N

The horizontal component of the tension on the rope (F*cos(θ)) is the force being applied to move the sled and that should equal the coefficient of friction multiplied by the normal force.

F*cos(\theta)=N*\mu\\5*cos(30)=26.9*\mu\\\mu=0.161

the coefficient of friction between the sled and the ground is 0.161

You might be interested in
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.
galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s

v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s

<u>Time taken to reach 1180 m is 11.29 seconds</u>

v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s

<u>Time the rocket will keep going up after the engines shut off is 13.06 seconds.</u>

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s

<u>Time taken by the rocket to fall from maximum height is 20.29 seconds</u>

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0
3 years ago
In your own words, explain Newton’s first law of motion.
Over [174]
Newton's first law of motion states that. an object on the rest or motion is stay the same unless external force applied on it.
5 0
3 years ago
Read 2 more answers
If the distance of a galaxy is 2,000 Mpc, how many years back into the past are we looking when we observe this galaxy
ruslelena [56]

The age of the galaxy when we look back is 13.97 billion years.

The given parameters:

  • <em>distance of the galaxy, x = 2,000 Mpc</em>

According Hubble's law the age of the universe is calculated as follows;

v = H₀x

where;

H₀ = 70 km/s/Mpc

T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\  \times \ years}{3600 \ s \ \times\  24\ h\  \times \ 365.25 \ days} \\\\T = 1.397  \times 10^{10} \ years\\\\T = 13.97 \ billion \ years

Thus, the age of the galaxy when we look back is 13.97 billion years.

Learn more about Hubble's law here: brainly.com/question/19819028

8 0
2 years ago
Which of the following is a potential result of preparing appropriately before starting an experiment in a lab?
oksano4ka [1.4K]

Answer:

Your project goes well.

Explanation:

Because that's how it works.

6 0
3 years ago
What type of current is produced by a battery?
nadya68 [22]
The type of current produced by a battery is direct current. C.
8 0
3 years ago
Read 2 more answers
Other questions:
  • A spring with a mass of 5 Kg has natural length 0.5m. A force of 35.6 N is required to maintain it stretched to a length of 0.5m
    11·1 answer
  • What brings greater concentration of dissolved nutrients to ocean surface
    6·2 answers
  • Since illness can be caused by bacteria that live in water, pollution in water can lead to serious illness. true or false
    8·1 answer
  • What causes light to bend when it moves from one transparent medium to another?
    9·2 answers
  • The element in an incandescent light bulb that releases light energy is
    14·1 answer
  • What type of weather is associated with a stationary front
    5·1 answer
  • A 1000 kg red car traveling at 40 m/s rear ends a 3000 kg blue car traveling at 35 m/s. the cars bounce off each other and the b
    10·1 answer
  • If you are about to be hit from behind, your best course of action is to brake gently and stop the car.
    7·1 answer
  • An object is moving with constant speed in a circular path. The object's centripetal acceleration remains constant in
    9·1 answer
  • Grey heated a cup of cocoa in the microwave. When she removed it from the microwave, the cocoa was too hot to drink, so she left
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!