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maria [59]
3 years ago
14

A child pulls a 3.00-kg sled across level ground at constant velocity with a light rope that makes an angle 30.0° above horizont

al. The tension in the rope is 5.00 N. Assuming the acceleration of gravity is 9.81 m/s2, what is the coefficient of friction between the sled and the ground?
Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

μ = 0.161

Explanation:

Since the tension on the rope (F) is being applied at an angle (θ), it should be decomposed into a vertical and a horizontal component.

The vertical component of the tension on the rope (F*sin(θ)) is pulling the sled upwards, decreasing the normal force.

Therefore, the normal force can be calculated as:

N = m*g - F*sin(\theta)\\N= 3*9.8 - 5*sin(30)\\N= 26.9 N

The horizontal component of the tension on the rope (F*cos(θ)) is the force being applied to move the sled and that should equal the coefficient of friction multiplied by the normal force.

F*cos(\theta)=N*\mu\\5*cos(30)=26.9*\mu\\\mu=0.161

the coefficient of friction between the sled and the ground is 0.161

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Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

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3 years ago
An x-ray beam of wavelength 1.4×10−10m makes an angle of 20° with a set of planes in a crystal(the Bragg angle)causing first ord
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Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

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Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

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1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

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\sin\theta_{1} =0.68

<em>θ₁ </em>= 43.33°

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2 years ago
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Answer:

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3 years ago
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5 0
3 years ago
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Answer:

The answer to your question is: letter D.

Explanation:

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8 0
3 years ago
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