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denpristay [2]
3 years ago
10

What is an “equilibrium temperature”?

Physics
1 answer:
RSB [31]3 years ago
6 0

Answer:

One may assume that the planet radiates energy like a blackbody at some temperature according to the Stefan–Boltzmann law. Thermal equilibrium exists when the power supplied by the star is equal to the power emitted by the planet. The temperature at which this balance occurs is the planetary equilibrium temperature.

Explanation:

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Assume your sampling frequency (fs) is 500 Hz. If you want to capture the 50Hz signal for 5 seconds, calculate the number of sam
belka [17]

Answer:

N = 2500

Explanation:

By definition, the sampling frequency (fs) is:

f_{s} = N / T

<em>where N: is the number of samples and T: is the time</em>

Hence, the number of samples at the sampling frequency, 500 Hz, to get 5 seconds of data is:

N = f_{s} \cdot T = 500 s^{-1} \cdot 5 s = 2500  

I hope it helps you!                        

3 0
4 years ago
1.A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upwar
Charra [1.4K]

Answer:

1. t = 3.27 seconds

2. y = 147.3 m

Explanation:

Newton's Laws of Motions.

y = v₁t + 1/2 at²

a = (v₂-v₁)/t

where

y = the vertical distance travelled

v₁ = the initial velocity

v₂ = the final velocity

t = the time

a = the acceleration

final velocity is equal to 0.

So, v₂ = 0.

a = (v₂-v₁)/t

a = (0-30)/t

a = -30/t

plugin values into the first equation:

y = v₁t + 1/2 at²

49 = 30t + 1/2 (-30/t)t²

49 = 30t -15t

49 = 15 t

t = 49/15

t = 3.27 seconds

2.

y = v₁t + 1/2 at²

a = -30/3.27

a = 9.2

y = 30(3.27) + 1/2(9.2) 3.27²

y = 147.3 m

6 0
4 years ago
A climber using bottled oxygen accidentally drops the oxygen bottle from an altitude of 4500 m. If the bottle fell straight down
Trava [24]

Answer:

v= 300 m/s

Explanation:

Given that

altitude ,h= 4500 m

The mass ,m = 3 kg

Lets take acceleration due to gravity , g= 10 m/s²

The speed before impact at sea  level =  v

Initial speed ,u = 0 m/s

We know that

v²=u²+2 g h

v=final speed

u=initial speed

h=height

Now by putting the values in the above equation

v² = 0²+ 2 x 10 x 4500

v²=90000

v= 300 m/s

Therefore the speed at sea level will be 300 m/s.

3 0
3 years ago
A sound wave has a frequency of 645 Hz in air
rodikova [14]

Answer:

-14.2^{\circ}C

Explanation:

First of all, we can find the speed of the sound wave, which is given by:

v=f \lambda

where

f = 645 Hz is the frequency

\lambda=0.5 m is the wavelength

Substituting,

v=(645 Hz)(0.5 m)=322.5 m/s

Now we can find the temperature of the air by using the following relationship:

v = 331 m/s + 0.6 T

where T is the temperature in Celsius degrees. Since we know v = 322.5 m/s, we can re-arrange the formula to find the temperature:

T=\frac{v-331 m/s}{0.6}=\frac{322.5 m/s-331 m/s}{0.6}=-14.2^{\circ}C

7 0
3 years ago
Fish are not able to regulate their body temperature by producing heat.
4vir4ik [10]

Answer:

evaporating water from its skin

6 0
3 years ago
Read 2 more answers
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