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alekssr [168]
4 years ago
8

John is pushing (horizontally) on a 100 kg bench with a force of 380 Newtons. What is the size of the friction force acting on t

he bench if the coefficient of static friction is 0.4? Where will the bench be 10 seconds after John starts pushing
Physics
2 answers:
Gnesinka [82]4 years ago
7 0

Answer:

dx = 0

Explanation:

<em>The Force of Friction = N * coefficient of static friction</em>

<em>N = m * g</em>

<em>=> The Force of Friction = m * g * coefficient of static friction</em>

The Force of Friction = 100 * 10 * 0.4 = 400 (N)

The Force of Friction > The Force of John

=> It won't move!

aliya0001 [1]4 years ago
4 0

Answer:

392 N, no movement

Explanation:

Im big brain

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