John is pushing (horizontally) on a 100 kg bench with a force of 380 Newtons. What is the size of the friction force acting on t

Question

4 years ago

8

he bench if the coefficient of static friction is 0.4? Where will the bench be 10 seconds after John starts pushing

2 answers:

Gnesinka [82] · Answer 1 · 2021-12-23T22:11:41+03:00

Answer:

dx = 0

Explanation:

The Force of Friction = N * coefficient of static friction

N = m * g

=> The Force of Friction = m * g * coefficient of static friction

The Force of Friction = 100 * 10 * 0.4 = 400 (N)

The Force of Friction > The Force of John

=> It won't move!

aliya0001 [1] · Answer 2 · 2021-12-23T20:16:52+03:00

4 0

Answer:

392 N, no movement

Explanation:

Im big brain