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I am Lyosha [343]
3 years ago
9

Suppose a mass of 0.500 kg falls from 3050m. What potential energy is associated with the coin when its speed is 30.0 m/s?

Physics
1 answer:
mojhsa [17]3 years ago
7 0

Just want your points

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Viefleur [7K]
For heating Solid, Liquid, Gas and for cooling the opposite Gas, Liquid, Solid
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3 years ago
Chromatic aberration occurs when:___.
worty [1.4K]

Answer:

b. a lens does not focus all colors of light to the same place.

Explanation:

Chromatic aberration is a defect of a lens. In this defect, the lens is unable to focus the different wavelengths of the light on a single focal point. It is also known as chromatic distortion and color fringing. It is caused by the dispersion of light while passing through a lens. As a result, the image might become blurred and different colors are observed around its edges. It can be corrected by the use of a combination of converging and diverging lenses.

Hence, the correct option will be:

<u>b. a lens does not focus all colors of light to the same place.</u>

4 0
3 years ago
if a 3-kg object has a momentum of 33 kg��m/s, what's its velocity? a. 99 m/s b. 36 m/s c. 11 m/s d. 9.1 m/s
horsena [70]
M=3kg
p=33kg.m/s
p=m*v
v=p/m
=33/3
=11m/s
thus option (c)
6 0
3 years ago
Read 2 more answers
If an ocean has a wavelength of 2 m and a frequency of 1 wave/s then it's speed is ___ m/s.
scoundrel [369]
V = f x lamda

Wave speed = frequency x wavelength
2x1 = 2 so wave speed = 2m/s

Let me know if you have any questions
7 0
3 years ago
A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two parallel conducting plates separa
Zanzabum

Answer:

E=8*10^5\frac{V}{m}

Explanation:

The magnitude of the electric field between two parallel conducting plates is defined as:

E=\frac{\Delta V}{d}

Here \Delta V is the potential difference between the plates and d its separation.

The electric potential energy is defined as the product between the particle's charge and the potential difference:

U=q\Delta V

Solving for \Delta V and replacing in the electric field formula:

\Delta V=\frac{U}{q}\\E=\frac{U}{qd}

In this case we have a double charged ion, so q=2e:

E=\frac{32*10^3eV}{(2e)(2*10^{-2}m)}\\E=8*10^5\frac{V}{m}

6 0
3 years ago
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