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I am Lyosha [343]
3 years ago
9

Suppose a mass of 0.500 kg falls from 3050m. What potential energy is associated with the coin when its speed is 30.0 m/s?

Physics
1 answer:
mojhsa [17]3 years ago
7 0

Just want your points

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A factory emits pollutants at a rate of 25 g/s. The factory is located between two mountain ranges resulting in an effective val
Lostsunrise [7]

Answer:

1.25\ \mu\text{g/m}^3

Explanation:

v = Velocity of the breeze = 4 m/s

w = Width of the valley = 5000 m

h = Height of the valley = 1000 m

Volumetric flow rate is given by

\dot{V}=vwh\\\Rightarrow \dot{V}=4\times 5000\times 1000\\\Rightarrow \dot{V}=2\times10^{7}\ \text{m}^3/\text{s}

\dot{m} = Mass flow rate of pollutant = 25 g/s = 25\times 10^6\ \mu\text{g/s}

Concentration is given by

C=\dfrac{\dot{m}}{\dot{V}}\\\Rightarrow C=\dfrac{25\times 10^6}{2\times 10^7}\\\Rightarrow C=1.25\ \mu\text{g/m}^3

The steady state concentration of pollutants in the valley, is 1.25\ \mu\text{g/m}^3.

6 0
3 years ago
if a ball on a string swung in a circles and string suddenly breaks.the ball will move into what direction?
Akimi4 [234]

Answer: b

Explanation: did the quiz got it right

3 0
3 years ago
A scientist observes and records data for the force of gravity between a star and a few different-sized planets. The planets are
user100 [1]

Answer: pppp

Explanation:This pp

3 0
3 years ago
Type the correct answer in the box. use numerals instead of words. anne has a sample of a substance. its volume is 20 cm3, and i
CaHeK987 [17]

The density of sample is 5 g/cm3

Given:

volume of sample = 20 cm3

mass of sample = 100 grams

To Find:

density of sample

Solution: Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick. It is defined as mass per unit volume

density = mass/volume

d = 100/20

d = 5 g/cm3

So, density of sample is 5 g/cm3

Learn more about Density here:

brainly.com/question/1354972

#SPJ4

6 0
1 year ago
. A mass m is traveling at an initial speed of 25.0 m/s. It is brought to rest in a distance of 62.5 m by a net force of 15.0 N.
harkovskaia [24]

Answer:

m = 3 kg

The mass m is 3 kg

Explanation:

From the equations of motion;

s = 0.5(u+v)t

Making t thr subject of formula;

t = 2s/(u+v)

t = time taken

s = distance travelled during deceleration = 62.5 m

u = initial speed = 25 m/s

v = final velocity = 0

Substituting the given values;

t = (2×62.5)/(25+0)

t = 5

Since, t = 5 the acceleration during this period is;

acceleration a = ∆v/t = (v-u)/t

a = (25)/5

a = 5 m/s^2

Force F = mass × acceleration

F = ma

Making m the subject of formula;

m = F/a

net force F = 15.0N

Substituting the values

m = 15/5

m = 3 kg

The mass m is 3 kg

7 0
3 years ago
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