The resistance of a conductor is given by
![R= \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%20)
where L is the length of the wire,
![\rho](https://tex.z-dn.net/?f=%5Crho)
the resistivity of the material and A the cross-sectional area.
We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length:
![L'=4 L](https://tex.z-dn.net/?f=L%27%3D4%20L)
, then the new resistance is also 4 times the original value:
Answer:
The answer is the kinetic energy of sled B after it crash is 6439j.
If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be
.
<h3>What is an escape velocity?</h3>
The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.
The formula to calculate the escape velocity of earth is given below:-
![V_e=\sqrt{\dfrac{2GM}{r}}](https://tex.z-dn.net/?f=V_e%3D%5Csqrt%7B%5Cdfrac%7B2GM%7D%7Br%7D%7D)
Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-
![V_e=\sqrt{\dfrac{2GM}{r\times 2}}](https://tex.z-dn.net/?f=V_e%3D%5Csqrt%7B%5Cdfrac%7B2GM%7D%7Br%5Ctimes%202%7D%7D)
.
Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be
.
To know more about escape velocity follow
brainly.com/question/14042253
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A person's weight will change if they move from the earth to the moon. This does not however, change the person's mass. Mass is the amount of matter that makes up an object, and volume is how much space it takes up. On the moon, there is a lighter gravitational pull on said person, so they will not weigh as much if they stepped on a scale.
Hey mate
Here is your answer
Option A)
Explanation:
The larger the amplitude of the waves, the louder the sound. Pitch (frequency) – shown by the spacing of the waves displayed. The closer together the waves are, the higher the pitch of the sound.
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