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AleksandrR [38]
3 years ago
5

Solve the equation-3x+25 = 40, we want to know the value of x

Mathematics
2 answers:
Mariulka [41]3 years ago
6 0

Answer:

Last option: x = -5

Step-by-step explanation:

-3x + 25 = 40

-3x = 40 - 25

-3x = 15

3x = -15

x = -5

german3 years ago
4 0

Answer:

x= -5

Step-by-step explanation:

-3x+25=40

subtract 25 from both sides

-3x=15

divide

x= -5

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Write a function for the situation. Is the graph continuous or discrete? A movie store sells DVDs for $11 each. What is the cost
Goshia [24]
B: because 11 times N will give you how much your cost would be . Example: 11*2= $22 if you bought 2 cds it would be $22. and its continuous cause youre going up at a constant rate.
7 0
3 years ago
Which is greater, 4.87 x 10^9 or 9.212 x 10^8? <br> please helpp
STatiana [176]

Answer: 4.87 x 10^9  is greater than 9.212 *10^8

Step-by-step explanation:

4.87 x 10^9  is greater than 9.212 *10^8 because it has the greater exponent.

4.87 * 10^9 =  4,870,000,000

9.212 *10^8= 921,200,000

4,870,000,000 > 921,200,000

6 0
3 years ago
The area of a 25 inch TV screen is 300 in.². The area of a 40 inch TV screen is 768 in.². The area of the smaller screen is what
Rina8888 [55]

Answer:

39.0625%

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The area of a 40 inch TV screen is 768in²

Percentage of area of the smaller screen to larger screen is;

300/768 × 100 = 39.0625%


5 0
4 years ago
Find the equation of a line parallel to y=6 that passes through (4,3)
ozzi

Answer: 4

Step-by-step explanation:

8 0
3 years ago
Un submarino se encuentra 50m por debajo del nivel del mar y comienza a subir 2m cada 5 minutos ¿a que profundidad se encuentra
Trava [24]

Answer:

a) El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

Step-by-step explanation:

a) De acuerdo con el enunciado, la cantidad de metros ascendidos por el submarino es directamente proporcional al tiempo, entonces la profundidad del submarino a la hora de haber comenzado el ascenso se obtiene mediante la siguiente relación lineal:

h = 50\,m - \frac{2\,m}{5\,min}\times 60\,min

h = 26\,m

El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) En primer lugar, calculamos el tiempo total del viaje mediante la siguiente relación:

\frac{2\,m}{5\,min} = \frac{50\,m}{t}

t = 50\,m\times \frac{5\,min}{2\,m}

t = 125\,min (2\,h\,5\,min)

El tiempo faltante para alcanzar la superficie se calcula mediante la siguiente sustracción:

\Delta t = 125\,min - 60\,min

\Delta t = 65\,min (1\,h\,5\,min)

Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

7 0
3 years ago
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