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4 years ago

A boat moves initially at 10 m/s, then accelerates at 2 m/s^2 for 10 s. What is the velocity of the boat after 10 s?

Physics

1 answer:

bija089 [108]4 years ago

6 0

Answer:

Explanation:

acceleration is the change in velocity of a body with respect to time

a = v-u/t

v is the final velocity

u is the initial velocity = 10m/s

t is the time taken = 10s

a is the acceleration = 2m/s²

substitute the values into the formula

2 = v-10/10

cross multiply

20 = v-10

v = 20+10

v = 30m/s

Hence the velocity of the body after 10s is 30m/s

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A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel

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After 6 seconds, the car will surpass the cyclist.

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The speed of the cyclist = 6 m/s.

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Read 2 more answers

A car accelerates uniformly from rest to speed 6.6 m/s in 6.5 s .Find the distance the car travel during this time .

kirill [66]

Answer:

<em>The distance the car traveled is 21.45 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It occurs when an object changes its velocity at the same rate thus the acceleration is constant.

The relation between the initial and final speeds is:

$v_f=v_o+at\qquad\qquad [1]$

Where:

a = acceleration

vo = initial speed

vf = final speed

t = time

The distance traveled by the object is given by:

$\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]$

Solving [1] for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:

$\displaystyle a=\frac{6.6-0}{6.5}$

$a = 1.015\ m/s^2$

The distance is now calculated with [2]:

$\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}$

x = 21.45 m

The distance the car traveled is 21.45 m

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3 years ago