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blsea [12.9K]
3 years ago
14

A car slams on its brakes, coming to a complete stop in 4.0 s. The car was traveling south at 60.0 mph. Calculate the accelerati

on.
Physics
2 answers:
Mashutka [201]3 years ago
7 0

Answer:

Acceleration, a=-6.705\ m/s^2

Explanation:

It is given that,

Velocity of the car, u = 60 mph = 26.82 m/s

Finally it comes to stop, v = 0

Time taken, t = 4 s

We need to find the acceleration of the car. The change in velocity divided by time is called the acceleration of the object. Mathematically, it is given by :

a=\dfrac{v-u}{t}

a=\dfrac{0-26.82}{4}

a=-6.705\ m/s^2

Negative sign shows the car is decelerating. So, the acceleration of the car is 6.705\ m/s^2. Hence, this is the required solution.

emmainna [20.7K]3 years ago
4 0
Acceleration = ms^(-1)
= 60/4
=15 ms with the power of -1
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What do I have to do to figure out " What % of an object’s mass is above the water line if the object’s density is 0.82g/ml " wi
blsea [12.9K]

Answer:

18%

Explanation:

There are two equal and opposite forces on a floating object: weight and buoyancy.

W = B

The weight of an object is its mass times gravity: W = mg

Buoyancy is the weight of the displaced fluid: W = mf g

Plugging in:

mg = mf g

m = mf

Mass is density times volume:

ρV = ρf Vf

Solving for the ratio of Vf / V:

Vf / V = ρ / ρf

Given that ρ = 0.82 g/mL and ρf = 1.00 g/mL:

Vf / V = 0.82

That means 82% of the object's volume (and therefore, 82% of its mass, assuming uniform density) is submerged.  Which means that 18% is above the water line.

4 0
4 years ago
(a) When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850m from the hinges. What tor
nadezda [96]

Explanation:

Below is an attachment containing the solution.

7 0
3 years ago
Displacement is which of the following types of quantities?A. vectorB. scalarC. magnitudeD. dimensional
agasfer [191]

Answer: A. vector

Explanation:

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6 0
3 years ago
Is the appearance of a light wave changed as it is aborted?
Sonbull [250]
Light waves are never 'aborted'. 

They can be 'absorbed', and I think that's what you mean. 
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"Absorb" just means "soak up".  When a light wave hits something and
gets soaked up in it, it's gone, and never comes out the other side.

The light wave certainly gets changed ... it no longer exists.

The object that absorbs it also gets changed.  It soaks up the energy
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7 0
3 years ago
A projectile is fired straight up from ground level. After t seconds it's height is above the ground is h feet where h=-16t^2+14
Rainbow [258]
<span>Plug in 288 for h, move it over to the right side and do the quadratic formula to solve for t. You will get 2 times, in between and including those times will give you the period it is at least 288 ft off the ground.

</span>You can simplify this and not need to use the quadratic. <span>288=−16<span>t^2</span>+144t
</span><span>Divide through by 16 getting
 18=-t^2 + 9t
</span><span><span>t^2</span>−9t+18=0</span><span> Is what you would get after rearranging the equation Now you have something you can easily factor</span><span>


</span>
5 0
3 years ago
Read 2 more answers
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