Answer:
300 m/s
Explanation:
As the cylinder drops off so its initial velocity is zero.
h = 4500 m, g = 10 m/s^2, u = 0
Use third equation of motion
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 10 x 4500
v^2 = 90000
v = 300 m /s
Answer:
Explanation:
From the information given:
The avg. velocity post the window is;
= velocity located at the top of the window
= velocity situated at the bottom of the window
Using the equation of kinematics:
Hence,
To determine the average velocity as follows:
where;
= velocity gained when fallen through the height h.
Similarly, using the equation of kinematics, we have;
Thus, the velocity at the ground is;
Answer:
8 seconds
Explanation:
as per 1st equation of motion
v=u+at,
u= initial velocity, v= final velocity , t=time, a=acceleration
since it starts from rest , u=0
v=16m/s
a=2m/s^2
16=0+2t
16=2t
t=8
Answer:
Explanation:
fundamental frequency, f = 250 Hz
Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.
the formula for the frequency is given by
.... (1)
Now the length is doubled ans the tension is four times but the mass remains same.
let the frequency is f'
.... (2)
Divide equation (2) by equation (1)
f' = √2 x f
f' = 1.414 x 250
f' = 353.5 Hz