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Ganezh [65]
3 years ago
14

Why did the producers and director decide to have the girls run outside to the water during the climactic moments of Act Three?

Physics
1 answer:
jolli1 [7]3 years ago
5 0
Is this a book and most likely because the were cute
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A toy car has a 1.5 A current, and its resistance is 2 . How much voltage does the car require?
Arisa [49]

Answer:

3 Volts

Explanation:

Using Ohm's Law

         Voltage=current x resistance

              V = I x R

              V = 1.5 x 2

              V = 3 V

6 0
3 years ago
Which of the following does not serve as a way to neutralize the charge in a body?
Brrunno [24]

Answer:

B. Adding more protons to a positively charged body until the number of protons matches the number of electrons

Explanation:

5 0
4 years ago
Which type of change releases a large amount of energy per gram of material as a result of the conversion of matter into energy?
kramer
B.) "Nuclear Change" <span> releases a large amount of energy per gram of material as a result of the conversion of matter into energy

Hope this helps!</span>
6 0
4 years ago
Read 2 more answers
a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w
nataly862011 [7]

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load  distance=10 cm

We have to find the effort distance.

We know that

load\times load\;distance=Effort\times effort\;distance

Using the formula

800\times 10=200\times effort\;distance

Effort distance=\frac{800\times 10}{200}

Effort distance=\frac{8000}{200}

Effort distance=40 cm

Hence,  the effort distance will be 40 cm.

7 0
3 years ago
Consider two particles A and B. The angular position of particle A, with constant angular acceleration, depends on time accordin
Vera_Pavlovna [14]

Answer:

θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

Explanation:

This is an angular kinematic exercise the equation for the angular position

the particle A

       θ = θ₀ + ω₀ t + ½ α t²

They say for the particle B

     w₀B = ½ w₀

     αB = 2 α

In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial

      t´ = t - t_1

l

et's write the equation of particle B

      θ = θ₀ + w₀B t´ + ½ αB t´2

replace

     θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²

     θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²

4 0
3 years ago
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