Given
m1(mass of the first object): 55 Kg
m2 (mass of the second object): 55 Kg
v1 (velocity of the first object): 4.5 m/s
v2 (velocity of the second object): ?
m3(mass of the object dropped): 2.5 Kg
The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:
Pa= Pb
Where Pa is the momentum before collision and Pb is the momentum after collision.
Now applying this law for the above problem we get
Momentum before collision= momentum after collision.
Momentum before collision = (m1+m2) x v1 =(55+5)x 4.5 = 270 Kgm/s
Momentum after collision = (m1+m2+m3) x v2 =(55+5+2.5) x v2
Now we know that Momentum before collision= momentum after collision.
Hence we get
270 = 62.5 v2
v2 = 4.32 m/s
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Answer:
20
Explanation:
20 multiplied by 2
hope i hv answered ur question
Answer:
a) 360 kQ
b) 4.32 MJ
c) 1200 W-h
Explanation:
a) The definition of the current is.
having a count that 10 hours = 36.000 s
![Q = 36000*10 = 360.000 [Q]](https://tex.z-dn.net/?f=%20Q%20%3D%2036000%2A10%20%3D%20360.000%20%5BQ%5D%20)
b) The definition of the Energy in power terms is.
and the definition of power is:
![P = V*I = 12 * 10 = 120 [W]](https://tex.z-dn.net/?f=%20P%20%3D%20V%2AI%20%3D%2012%20%2A%2010%20%3D%20120%20%5BW%5D)
replacing in the energy formula.
solving the integral, have into account that t is in seconds.
![E=P*t=120*36000=4.320.000=4.32 [MJ]](https://tex.z-dn.net/?f=%20E%3DP%2At%3D120%2A36000%3D4.320.000%3D4.32%20%5BMJ%5D)
c) The energy in W-h, we can find it multiplying power by hours
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