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The special ____________________________________ of the vegetation.

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ELEN [110]3 years ago

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Calculate the diffusive force (J) experienced by potassium in a cell where the concentration gradient is 35 mM, the membrane wid

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Diffusive force J = 9590

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From the given information:

Concentration gradient C₁ - C₂ = 35 mM = 35 × 10⁻³ M

membrane width Δ x = 1 cm = 10⁻² m

Solubility S = 1

diffusive area A = 10

Temperature T = 1° C = (273 + 1 )K = 274 K

Using the expression:

$\text {diffusive force J} = \dfrac{C_1-C_2}{\Delta x }\times T \times S \times A$

$J = \dfrac{35 \times 10^{-3}}{10^{-2} }\times 274 \times 1 \times 10$

$J = 3.5 \times 274 \times 1 \times 10$

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