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maksim [4K]
4 years ago
7

Ocean acidification impacts ocean species to varying degrees. While most of the impacts are negative when considering ocean acid

ification, there can be positive impacts as well. Which of these COULD be a POSITIVE impact of ocean acidification?
Physics
2 answers:
Pavlova-9 [17]4 years ago
4 0

Answer: Answer D Photosynthetic algae and sea grasses

Explanation:

elena55 [62]4 years ago
3 0

Answer:

Researchers have discovered the positive impact of moderately elevates carbon dioxide own to Ocean acidification. Also the growth rate of one reef-building coral actually improved with moderate ocean acidification.

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An alternating-current (AC) source supplies a sinusoidally varying voltage that can be described with the function v of t is equ
Marrrta [24]

Answer:

ω, the angular frequency of the source equals 377 rad/s

Explanation:

From the question, V(t) = V cosωt.

Now, ω = the angular frequency of the sinusoidal wave is given by

ω = 2πf where f = the frequency of the source = 60 Hz

So, the angular frequency of the source ,ω = 2π × the frequency of the source.

So, ω = 2πf

ω = 2π × 60 Hz

ω = 120π rad/s

ω = 376.99 rad/s

ω ≅ 377 rad/s

So, ω, the angular frequency of the source equals 377 rad/s

3 0
3 years ago
Two identical metal spheres a and b are connected by a plastic rod. both are initially neutral. 1.0×1012 electrons are added to
Ann [662]
The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.

The number of electrons initially given to sphere A is N=1.0 \cdot 10^{12}, and since the charge of 1 electron is e=-1.6 \cdot 10^{-19} C, the net charge left on sphere A after the removal of the rod will be
Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C
8 0
3 years ago
Read 2 more answers
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg
slava [35]

Answer:

Explanation:

mass of first marble m_1=m=0.015\ kg

Initial velocity of the first marble u_1=22.5\ m/s

considering right side as positive

Mass of second marble

m_2=m=0.015\ kg\\u_2=-18\ cm/s

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. v_1=-18\ cm/s

considering v_2 be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

e=\frac{v_2-v_1}{u_1-u_2}

Putting values

1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy =0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J

Final kinetic energy=

0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J

6 0
3 years ago
HEL ME PLEASE I HAVE NO IDEA OF WHAT TO DO!!!!!!
Dahasolnce [82]

Answer:

b, the fastest the car has traveled out of those options is 4-5 seconds.

Explanation:

3 0
3 years ago
Read 2 more answers
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

6 0
3 years ago
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